Answer:
There are vertical asymptotes at x: {-1, 0, 5}
Step-by-step explanation:
It's easier (at least for some) if you write this function as
3
F(X) = ------------------
x(x-5)(x+1)
Can you now see that if x = 0, this function is undefined? Same for x = 5 and x = -1? There are vertical asymptotes at x: {-1, 0, 5}