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never [62]
3 years ago
8

Find the value of X.

Mathematics
2 answers:
Scilla [17]3 years ago
8 0
All exterior angles of a hexagon must add up to 360

a_sh-v [17]3 years ago
4 0

Answer:

53°

Step-by-step explanation:

Total exterior angle = 360

x + x + 59 + 48 + 50 + 39 + 58 = 360

2x = 360 - 254

2x = 106

x = 53°

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Perfect square of u^2 - 14u + _
Rudiy27

The solution is in the attached file

5 0
2 years ago
Find the volume of the cylinder. Use pi = 3.14* the height of 6 inches and a radius 4.5in​
ArbitrLikvidat [17]

Answer: 381.51 cubic inches

Step-by-step explanation:

1. Use the formula: V = πr^{2}h, or in this case, 3.14(4.5^{2})(6)

2. Simplify to 3.14(20.25)(6)

3. Simply multiply all three numbers using a calculator, or one by one if that's the preferred option.

4. You get: 381.51 cubic inches.

8 0
3 years ago
Eva incorrectly classifies the quotient -(-81/-9) as positive.
NISA [10]
The answer is negative because, ( -81/-9) =(+9). -(+9) = -9. Maybe for got the - sign before the equation
6 0
3 years ago
What number is 25% of 5/8
sergij07 [2.7K]

Answer:

5/32 or .15625

Step-by-step explanation:

5/8=.625x.25=5/32 or .15625

3 0
2 years ago
A sample of 11001100 computer chips revealed that 62b% of the chips fail in the first 10001000 hours of their use. The company's
STALIN [3.7K]

Answer:

Rule

If;

P-value > significance level --- accept Null hypothesis

P-value < significance level --- reject Null hypothesis

Z score > Z(at 90% confidence interval) ---- reject Null hypothesis

Z score < Z(at 90% confidence interval) ------ accept Null hypothesis

Null hypothesis: H0 = 0.60

Alternative hypothesis: Ha <> 0.62

z score = 1.35

P value = P(Z<-1.35) + P(Z>1.35) = 0.0885 + 0.0885= 0.177

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = 1.35) falls with the region bounded by Z at 0.1 significance level. And also the two-tailed hypothesis P-value is 0.177 which is greater than 0.1. Then we can conclude that we don't have enough evidence to FAIL or reject the null hypothesis, and we can say that at 0.10 significance level the null hypothesis is valid.

Question; A sample of 1100 computer chips revealed that 62% of the chips fail in the first 1000 hours of their use. The company's promotional literature states that 60% of the chips fail in the first 1000 hours of their use. The quality control manager wants to test the claim that the actual percentage that fail is different from the stated percentage. Determine the decision rule for rejecting the null hypothesis, H0, at the 0.10 level.

Step-by-step explanation:

Given;

n=1100 represent the random sample taken

Null hypothesis: H0 = 0.60

Alternative hypothesis: Ha <> 0.62

Test statistic z score can be calculated with the formula below;

z = (p^−po)/√{po(1−po)/n}

Where,

z= Test statistics

n = Sample size = 1100

po = Null hypothesized value = 0.60

p^ = Observed proportion = 0.62

Substituting the values we have

z = (0.62-0.60)/√{0.60(1-0.60)/1100}

z = 1.354

z = 1.35

To determine the p value (test statistic) at 0.01 significance level, using a two tailed hypothesis.

P value = P(Z<-1.35) + P(Z>1.35) = 0.0885 + 0.0885= 0.177

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = 1.35) falls with the region bounded by Z at 0.1 significance level. And also the two-tailed hypothesis P-value is 0.177 which is greater than 0.1. Then we can conclude that we don't have enough evidence to FAIL or reject the null hypothesis, and we can say that at 0.10 significance level the null hypothesis is valid.

3 0
3 years ago
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