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never [62]
3 years ago
8

Find the value of X.

Mathematics
2 answers:
Scilla [17]3 years ago
8 0
All exterior angles of a hexagon must add up to 360

a_sh-v [17]3 years ago
4 0

Answer:

53°

Step-by-step explanation:

Total exterior angle = 360

x + x + 59 + 48 + 50 + 39 + 58 = 360

2x = 360 - 254

2x = 106

x = 53°

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Which of these statements is true
Eva8 [605]

Answer:

B:  The y-intercept is (0,2).

Step-by-step explanation:

See attached graph.

7 0
2 years ago
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Ann took a taxi home from the airport. The taxi fare was $2.10 per mile, and she gave the driver a tip of $5. Ann paid a total o
adell [148]

Answer:

$2.10x + 5= $49.10

x=21

Step-by-step explanation:

the x is used for a variable that changes and in this case the mph changes which lead x being the amount of miles that they had drove which at the end ends up multi. with the $2.10 . as for the 5 it was an initial as in it doesn't change.

for the second part

you subtract 5 from each side so you have the total of 2.10x= 44.10 then u divide 2.10 from each side and that will give you x = 21

3 0
3 years ago
Units are squared when dealing with area but not when dealing with perimeter
Mashcka [7]
The answer is true I believe 
7 0
3 years ago
The distance from a to B is 42 feet. The slope of the roof is 24 feet. What is the height of the attic
Hoochie [10]

well... 42+24=66 so the height of the attic is 66 feet

8 0
3 years ago
Mr. Jones' other friend Ms. O'Neill has "x" meters of fencing, what is the maximum area in square meters she can have?
Alexus [3.1K]

Answer:

Max\ Area = \frac{x^2}{16}

Step-by-step explanation:

Given

P = x ---- the perimeter of fencing

Required

The maximum area

Let

L \to Length

W \to Width

So, we have:

P = 2(L + W)

This gives:

2(L + W) = x

Divide by 2

L + W = \frac{x}{2}

Make L the subject

L = \frac{x}{2} - W

The area (A) of the fence is:

A = L * W

Substitute L = \frac{x}{2} - W

A = (\frac{x}{2} - W) * W

Open bracket

A = \frac{x}{2}W - W^2

Differentiate with respect to W

A' = \frac{x}{2} - 2W

Set to 0

\frac{x}{2} - 2W = 0

Solve for 2W

2W = \frac{x}{2}

Solve for W

W = \frac{x}{4}

Recall that:

L = \frac{x}{2} - W

L = \frac{x}{2} - \frac{x}{4}

L = \frac{2x- x}{4}

L = \frac{x}{4}

So, the maximum area is:

A = L * W

A = \frac{x}{4}*\frac{x}{4}

Max\ Area = \frac{x^2}{16}

8 0
3 years ago
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