Question

ONE HUNDRED POINTS

Answer 1

Answer:

See Below.

Step-by-step explanation:

We are given that ∠A = ∠D, and we want to prove that ΔACB ~ ΔDCE.

Statements:                                    Reasons:

$1) \angle A=\angle D$                                    $\text{Given}$

$2) \text{ }\angle BCA=\angle ECD$                        $\text{Vertical Angles Are Congruent}$

$3) \text{ } \Delta ACB \sim \Delta DCE$                        $\text{AA (Angle-Angle) Similarity}$

Answer 2

Given:

$\angle \: A = \angle D$

To prove:

ACB ~ DCE

Statement:

Given,

$\bf\angle \: A = \angle D$

$\bf \angle \: BCA= \angle \: ECD$

[ vertical angles ]

$\therefore \: ACB \sim DCE$

Reason:

By AA Criterion of similarity