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3 years ago

A Grocery store sells steak for $6.10 per pound.What would be the cost of 2 3/5 LB of steak?

Mathematics

1 answer:

77julia77 [94]3 years ago

8 0

<h2>Answer:</h2>

<u>The cost would be </u><u>$15.86</u>

<h2>Step-by-step explanation:</h2>

The cost of 1 steak is $6.10

The cost of 2 3/5 steaks will be

Cost of 2 3/5 steaks = 6.10 * 2 3/5

Cost of 2 3/5 steaks = $15.86

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Given tan theta =9, use trigonometric identities to find the exact value of each of the following:_______

Ludmilka [50]

Answer:

$(a)\ \sec^2(\theta) = 82$

$(b)\ \cot(\theta) = \frac{1}{9}$

$(c)\ \cot(\frac{\pi}{2} - \theta) = 9$

$(d)\ \csc^2(\theta) = \frac{82}{81}$

Step-by-step explanation:

Given

$\tan(\theta) = 9$

Required

Solve (a) to (d)

Using tan formula, we have:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

This gives:

$\frac{Opposite}{Adjacent} = 9$

Rewrite as:

$\frac{Opposite}{Adjacent} = \frac{9}{1}$

Using a unit ratio;

$Opposite = 9; Adjacent = 1$

Using Pythagoras theorem, we have:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 9^2 + 1^2$

$Hypotenuse^2 = 81 + 1$

$Hypotenuse^2 = 82$

Take square roots of both sides

$Hypotenuse =\sqrt{82}$

So, we have:

$Opposite = 9; Adjacent = 1$

$Hypotenuse =\sqrt{82}$

Solving (a):

$\sec^2(\theta)$

This is calculated as:

$\sec^2(\theta) = (\sec(\theta))^2$

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

Where:

$\cos(\theta) = \frac{Adjacent}{Hypotenuse}$

$\cos(\theta) = \frac{1}{\sqrt{82}}$

So:

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

$\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2$

$\sec^2(\theta) = (\sqrt{82})^2$

$\sec^2(\theta) = 82$

Solving (b):

$\cot(\theta)$

This is calculated as:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

Where:

$\tan(\theta) = 9$ ---- given

So:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

$\cot(\theta) = \frac{1}{9}$

Solving (c):

$\cot(\frac{\pi}{2} - \theta)$

In trigonometry:

$\cot(\frac{\pi}{2} - \theta) = \tan(\theta)$

Hence:

$\cot(\frac{\pi}{2} - \theta) = 9$

Solving (d):

$\csc^2(\theta)$

This is calculated as:

$\csc^2(\theta) = (\csc(\theta))^2$

$\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2$

Where:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

$\sin(\theta) = \frac{9}{\sqrt{82}}$

So:

$\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2$

$\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2$

$\csc^2(\theta) = \frac{82}{81}$

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If 4/3divided by 1/6 then the value of p is between which of the following pairs of numbers

Lerok [7]

Answer:

7 and 9

Step-by-step explanation:

4/3÷1/6 = 4/3 × 6/1

= 8

So the value of p falls between the range of 7 and 9

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How do you solve linear equations using substitution

GuDViN [60]

You substitute the y from the second eqaution to the y in the first equation

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Simplify.<br>(+18)%(-6)

Arisa [49]

Answer: -3

Step-by-step explanation:

18/6 = 3

18/-6 = -3

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The meaning of significance. Asked to explain the meaning of "statistically significant at the α=0.05 level," a student says: "T

Irina18 [472]

Answer:

This explanation is not correct

Explanation:

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If we wish to reach a conclusion on rejection or acceptance of the null hypothesis, we could use the p value(the probability that observed results or more extremee results are true given null hypothesis)which we compare with the significance level to conclude. If the significance level is 0.10 and p value is 0.07(since p value is less than significance level) , we reject the null hypothesis and vice versa.

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