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pentagon [3]
3 years ago
13

ACME Corp. is developing a software program that can run on mobile devices so that customers can interact with the firm, view pr

oduct information, and order status. This is best described as a(n) ___________.
Computers and Technology
1 answer:
dimaraw [331]3 years ago
5 0

Answer:

App is the correct answer of this question.

Explanation:

ACME Corp. is creating a computer program that can run on mobile devices to allow clients to communicate with the business, display product information and order status.This is best represented as app.

<u>For Example</u>:- Music,Playing games,text,video chatting,Shopping Online and Planning vacations etc.  

  • An app is a software category that allows you manage complex tasks.
  • Tablet or smartphone apps are sometimes pointed to as web browsers, while those for mobile devices are pointed to as apps and websites.

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Implement function hex2dec that takes a hex number hex_num as a string argument and prints out the corresponding decimal number.
DerKrebs [107]

Answer:

Check the explanation

Explanation:

#include <iostream>

using namespace std;

void hex2dec(string hex_num){

int n = 0;

//Loop through all characters in string

for(int i=0;i<hex_num.size();i++){

//take ith character

char c = hex_num[i];

//Check if c is digit

if(c>='0' && c<='9'){

n = 16*n + (c-48);

}

//Convert c to decimal

else{

n = 16*n + (c-55);

}

}

cout<<hex_num<<" : "<<n<<endl;

}

int main()

{

hex2dec("EF10");

hex2dec("AA");

return 0;

}

The Output can be seen below :

4 0
3 years ago
During boom times, which of the
pashok25 [27]
I think the answer is D.
3 0
3 years ago
Modify the list according to the following: append the smallest value at the end of the list when all numbers in the list are ne
ddd [48]

Answer:

The solution code is written in Python 3:

  1. def modifyList(listNumber):
  2.    posCount = 0
  3.    negCount = 0
  4.    for x in listNumber:
  5.        if x > 0:
  6.            posCount += 1
  7.        else:
  8.            negCount += 1
  9.    
  10.    if(posCount == len(listNumber)):
  11.        listNumber.append(max(listNumber))
  12.    
  13.    if(negCount == len(listNumber)):
  14.        listNumber.append(min(listNumber))
  15.    
  16.    print(listNumber)
  17. modifyList([-1,-99,-81])
  18. modifyList([1,99,8])
  19. modifyList([-1,99,-81])

Explanation:

The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).

To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).

If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).

If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.

At last we can print the listNumber (Line 17).

If we test our function using the three sets of input list, we shall get the following results:

[-1, -99, -81, -99]

[1, 99, 8, 99]

[-1, 99, -81]

3 0
3 years ago
A high school in New York (school A) is using videoconferencing technology to establish student interactions with another high s
Montano1993 [528]

Answer: This is private IP address

Explanation:

192.168.25.10 is a private IP address and is reserved for use only within an organisation so it cannot be used to communicate with the outside world. So in order to have videoconferencing they have to share their public IP addresses.

4 0
3 years ago
বর্তমান করােনার ন্যায় পরিস্থিতি অর্থাৎ স্বাভাবিক শ্রেণি কার্যক্রম পরিচালনা সম্ভব
Zarrin [17]

Answer:

ayo fam

Explanation:

I dont think this is supposed to be here lol

5 0
3 years ago
Read 2 more answers
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