Question

What is the length of a diagonal brace that could be used for a wall 9 feet high and 12 feet long?

Answer 1

Answer:

The correct answer is option 1.

Step-by-step explanation:

Height of the wall = p = 9 ft (Perpendicular)

length of the of the base of the wall = b = 12 ft (Base)

Length of the diagonal brace = h = ?(Hypotenuse)

Applying Pythagoras theorem ;

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(Hypotenuse)^2=(9 ft)^2+(12 ft)^281 ft^2+144 ft^2$

$(Hypotenuse)=\sqrt{225 ft^2}=15 ft$

15 feet is the length of a diagonal brace.