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andreev551 [17]
2 years ago
6

If f(x) = x^3 – 10x^2 + 29x – 30 and f(6) = 0, then find all of the zeros of f(x) algebraically.

Mathematics
1 answer:
tino4ka555 [31]2 years ago
7 0
Step 1: 1

(((x3) - (2•5x2)) + 29x) - 30 = 0

Step 2 2.1 x3-10x2+29x-30 is not a perfect cube

Step 3 Factoring: x3-10x2+29x-30

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 29x-30
Group 2: -10x2+x3

Pull out from each group separately :

Group 1: (29x-30) • (1)
Group 2: (x-10) • (x2)

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blagie [28]

Traveling m miles on this taxi costs

c=2.5+3.25m

In fact, we spend 2.50 no matter what, and then we add 3.25 (i.e. the cost of a mile) multiplied by the number of miles.

This quantity has to be less than or equal to 61, so we have

2.5+3.25m\leq 61

Solving for m, we start by subtracting 2.5 from both sides:

3.25m\leq 58.5

Then, we divide both sides by 3.25:

m\leq 18

8 0
3 years ago
Split the number 76 into the ratio 6:3:7:3 .
kompoz [17]

Answer:

24:12:28:12

Step-by-step explanation:

76÷19=4

6×4:3×4:7×4:3×4

=24:12:28:12

3 0
3 years ago
Alex reads about 200 words per minute. The book he needs to read is 320 pages long and has about 275 words per page. How many ho
grandymaker [24]

Answer:

7.3333 hours

Step-by-step explanation:

if im wrong oh well lol 275x320=88000 divided by 200 =440 divided by 60=7.3333

5 0
1 year ago
Suppose that y varies inversely with x and y = 3 when x=10 find y when x=5
zysi [14]

Answer:

y=1.5

Step-by-step explanation:

if (y = 3) is  (x = 10) and (y = ?) is (x = 5) we see that x is half of the first equation in the second. This means we divide both variables in the first equation by half to get the second. [(x = 10) / 2 = (x = 5)] therefor, [(y = 3) / 2 = (y = 1.5)]. Making your answer 1.5.

Hope this helps :)

4 0
3 years ago
Graph linear system and estimate the solution y=5x + 2 y=3x
NeTakaya
Y = 5x + 2
y = 3x

  5x + 2 = 3x
- 5x        - 5x
          2 = -2x
         -2    - 2
         -1 = x
y = 3x
y = 3(-1)
y = -3
(x, y) = (-1, -3)

3 0
3 years ago
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