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shepuryov [24]
3 years ago
13

Would somebody let me use their brainly so i can do work

Mathematics
2 answers:
Burka [1]3 years ago
6 0

Answer:

just watch the ads

Step-by-step explanation:

horrorfan [7]3 years ago
3 0
I do stop cheating it’s a very bad look
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Distribute and simplify these radicals. I need help!
notka56 [123]

Answer:

The last one (4 sqare root 3)

Step-by-step explanation:

The square root of 16 is 4 so then it would be 4 sqroot 3

3 0
2 years ago
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A party rental company has chairs and tables for rent. The total cost to rent
Paha777 [63]

Let c= cost to rent each other

Let t= cost to rent each other

2c+3t=25

6T+5T=49

Multiply the 2nd equation by (-2) and add equation together  

2c+3t=25

-12c-10t= 98

2t=98

T=49

Put this value into the 1st equation solve c

2c+3(49)=49

2c+147=49

2c=98

C=49

Cost to each chair and table are same 49.


4 0
3 years ago
How to divide 457 by 4
Basile [38]
Do you need to show your work? the answer is 114.25
3 0
3 years ago
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Can anyone please help!!!
quester [9]

Answer:

Question 9

(a) The distance, Jalaj walks in one day is 4.4 km

(b) The amount Jalaj raises after walking for 22 km at the end of the 5 days is $8

Question 10

(b) The difference between the largest and smallest areas is 2,400 m²

Step-by-step explanation:

Question 9

(a) The distance Jalaj walks in 5 days = 22 km

Whereby Jalaj walks equal distance every day, we have;

The distance, Jalaj walks in one day = 22 km/5 days = 4.4 km/day

The distance, Jalaj walks in one day = 4.4 km

(b) The amount he raises for every kilometer he walks = $1.60

The amount he raises after walking for 22 km at the end of the 5 days = 5 × $1.60  = $8

Question 10

(b) The given side length of the square = 120 meters to the nearest 10 meters

Therefore;

The maximum dimension for the side length of the square = 120 + 10/2 = 125

The largest possible area of the square, A_l = 125 m × 125 m = 15,625 m²

The minimum dimension for the side length of the square = 120 m - 10 m/2 = 115 m

The smallest possible area of the square, A_s = 115 m × 115 m = 13,225 m².

The difference between the largest and smallest areas, A_l - A_s = 15,625 - 13,225 = 2,400 m².

8 0
2 years ago
What is the horizontal asymptote of j(x) =
Korvikt [17]

Answer: y=7

Step-by-step explanation:

8 0
3 years ago
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