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fomenos
3 years ago
9

Describe some data that when graphed would represent a proportional relationship. Explain your reasoning

Mathematics
2 answers:
OLga [1]3 years ago
7 0
The lines would go up and over at the same rate. They would have the same slope, like parallel lines.

Hope this helps!! :)
Alex787 [66]3 years ago
7 0

Answer:

A proportional relationship is "two quantities vary directly with each other."

Example:

The amount of gasoline you fill in your car and the amount you pay is a proportional relationship.

If 1 gallon of gasoline is $3, then the cost of 3 gallons of gasoline is $9.

Step-by-step explanation:

A relationship is between two quantities.

A proportional relationship is "two quantities vary directly with each other."

Say, if the quantity "x" increases, then the associated quantity "y" also increases.

For example,

y = 2x

Let's find the data.

<u>x </u>                <u>y</u>

0                 0

1                  2

2                 4

3                  6

As you can see when the value of "x" increases, the value of "y" also increases.

This is called proportional relationship.

Example:

The amount of gasoline you fill in your car and the amount you pay is a proportional relationship.

If 1 gallon of gasoline is $3, then the cost of 3 gallons of gasoline is $9.

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y2=-8x is what's graphed so B.

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you measure the period of a mass oscillating on a vertical spring ten times as follows: period (s): 1.06, 1.31, 1.28, 0.99, 1.48
lidiya [134]

The mean and (sample) standard deviation σ = 0.2098.

<h3>What exactly would the standard deviation indicate?</h3>

The term "standard deviation" (or "") refers to the degree of dispersion of the data from the mean. Data are grouped around the mean when the standard deviation is low, and are more dispersed when the standard deviation is high.

<h3>According to given information:</h3>

The mean is the product of the dataset's total and the sample size. Mathematically.

\bar{x}=\frac{\sum X_i}{N}

The individual periods are Xi.

The sample size is N.

\sum X i = 1.06 + 1.31 + 1.28 + 0.99,+  1.48 + 1.37+  0.98 + 1.31 + 1.59 + 1.55

\sum X i = 12.92

N = 10

While substituting the value we get:

x = 12.96/10

x = 1.292

The samples' average is 1.292.

The standard deviation:

\sigma=\sqrt{\frac{\sum(x-\bar{x})^2}{N}}

\sum(x-\bar{x})^2 = (1.48-1.292)^2+(1.37-1.292)^2+(0.98-1.292)^2+(1.31-1.292)^2+(1.59-1.292)^2+(1.55-1.292)^2.

\sum(x-\bar{x})^2 = 0.43996

Putting into the formula we get:

\sigma=\sqrt{\frac{0.43996}{10}}

σ = √(0.043996)

σ = 0.2098

The mean and (sample) standard deviation σ = 0.2098.

To know more about standard deviation visit:

brainly.com/question/18521100

#SPJ4

I understand that the question you are looking for is:

You measure the period of a mass oscillating on a vertical spring ten times as follows:

Period (s): 1.06, 1.31, 1.28, 0.99, 1.48, 1.37, 0.98, 1.31, 1.59, 1.55

Required:

What are the mean and (sample) standard deviation?

a. Mean: 1.228, Standard Deviation: 0.2135

b. Mean: 1.325, Standard Deviation: 0.1674

c. Mean: 1.292. Standard Deviation: 0.2211

d. Mean: 1.228, Standard Deviation: 0.2098

e. Mean: 1.292, Standard Deviation: 0.2135

7 0
1 year ago
What is the area of the figure?
Korolek [52]

Answer:

Step-by-step explanation:

I think its the second one.

3 0
3 years ago
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