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ANEK [815]
3 years ago
7

Which graph shows a negative rate of change for the interval 0 to 2 on the x-axis?

Mathematics
1 answer:
PolarNik [594]3 years ago
4 0

Answer:

Step-by-step explanation:

help

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Solve -6 4/9-3 2/9-82/9
Gala2k [10]

Answer: The final answer in proper fraction is 169/9

Step-by-step explanation:

Given the expression

-6 4/9-3 2/9-82/9

Firstly let us convert all mixed fraction to proper fraction to further simplify the expression

-58/9 - 29/9 - 82/9

We now have all terms in proper fraction, we can continue by finding the LCM which is 9

= (- 58-29-82)/9

= 169/9

8 0
3 years ago
Use the given information to find the p-value. also use a0.05 significance level and state the conclusion about the null hypothe
omeli [17]

Answer:

(a) C: 0.0465 ; reject the null hypothesis

(b) B: 0.3409 ; fail to reject the null hypothesis

Step-by-step explanation:

Firstly, the decision rule based on P-value to reject the null hypothesis or fail to reject the null hypothesis is given by;

  • If the P-value of test statistics is less than the level of significance, then we have sufficient evidence to reject our null hypothesis.
  • If the P-value of test statistics is more than the level of significance, then we have insufficient evidence to reject our null hypothesis due to which we fail to reject our null hypothesis.

(a) Now, we are given alternate hypothesis, H_1 : p < 3/5

Also, z test statistics is -1.68. Since this is a left tailed test, so P-value is given by;

             P-value = P(Z < -1.68) = 1 - P(Z \leq 1.68)

                           = 1 - 0.95352 = <u>0.0465</u>

Since, the P-value of test statistics is less than the level of significance as 0.0465 < 0.05, so we have sufficient evidence to reject our null hypothesis due to which <u>we reject the null hypothesis.</u>

(b) Now, we are given alternate hypothesis, H_1 : p > 0.383

Also, z test statistics is 0.41. Since this is a right tailed test, so P-value is given by;

             P-value = P(Z > 0.41) = 1 - P(Z \leq 0.41)

                           = 1 - 0.6591 = <u>0.3409</u>

Since, the P-value of test statistics is more than the level of significance as 0.3409 > 0.05, so we have insufficient evidence to reject our null hypothesis due to which <u>we fail to reject the null hypothesis.</u>

5 0
3 years ago

jekas [21]

Given: In the given figure, there are two equilateral triangles having side 50 yards each and two sectors of radius (r) = 50 yards each with the sector angle θ = 120°

To Find: The length of the park's boundary to the nearest yard.

Calculation:

The length of the park's boundary (P) = 2× side of equilateral triangle + 2 × length of the arc

or,                    (P) = 2× 50 yards + 2× (2πr) ( θ ÷360°)

or,                    (P) = 2× 50 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)

or,                    (P) = 100 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)

or,                    (P) = 100 yards + 209.33 yards

or,                    (P) = 309.33 yards ≈309 yards

Hence, the option D:309 yards is the correct option.

7 0
3 years ago
Read 2 more answers
A manufacturer ships its product in boxes with
Alla [95]
3 would be the volume  hopes this is good 
7 0
3 years ago
Read 2 more answers
the ratio of the length of shantels pool to the length of juan's pool is 3 to 5 shantels pool is 30 meters how long is Juan’s po
love history [14]

Step-by-step explanation:

the ratio of the pool lengths is 3/5.

that means for every 3 meters of length on Shantel's pool, there are 5 meters of length on Juan's pool.

it the other way around : to get to the size of Shantel's pool, every 5 meters of length on Juan's pool are converted to 3 meters.

x = length of Juan's pool

x × 3/5 = 30

3x = 150

x = 50 meters

you see the relationship ?

3/5 = 30/50 = 300/500 = ...

but it is true for any factor

3/5 = 15/25 = 24/40 = 6/10 = ...

once you see the factor for one part of the ratio, you know there is the same factor for the other part (or parts) of the ratio. otherwise the ratio would not stay the same and keep the relationship.

3 0
2 years ago
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