Answer:
8022.
Step-by-step explanation:
Let x be the number of years after 2010.
We have been given a population of fish in a lake is 14000 in 2010. The population decreases 6% annually.
We can see that population of fish is the lake is decreasing exponentially as it is decreasing 6% annually.
Since we know that an exponential function is in form:
, where,
a = Initial value,
b = For decrease or decay b is in form (1-r) where r represents decay rate in decimal form.
Let us convert our given decay rate in decimal form.

Upon substituting our given values in exponential form of function we will get the population of fish in the lake after x years as:


Let us find x by subtracting 2010 from 2019.

Upon substituting x=9 in our function we will get,



Therefore, the population of fish in 2019 will be 8022.
¡Hola!
Your answer to the question is 10/12.
Step-by-step explanation:
By using the y^2-y^1/x^2-x^1
12-2= 10
16-4= 12
So your answer is 10/12.
Hope this Helps!
See attachment for the 3 Answers.
Answer: C. y = 10x + 15
Step-by-step explanation:
He has already watched 15 movies so that's plus 15
And now he wants to watch 10 movies per week, we don't know how many weeks so that's '<em>x</em>' in this equation.
If he watches movies for <em>x </em>weeks that's 10 times <em>x </em>which is the 10x in the equation.
Hope that helped!
Answer:
Step-by-step explanation:
- log8(216) + [log(42) - log(6)] ÷ log(49) =
- log (216)/ log (8) + [log (7) + log (6) - log (6)] ÷ 2 log (7) =
- 3 log (3) log (2) / 3 log (2) + log (7) / 2 log (7) =
- 3 log (3) + 1/2