Answer:
The work required to stretch a spring 12 ft beyond its natural length is 432 ft-lb
Explanation:
The work to stretch a spring is calculated using the formula:
Equation (1)
W = work in ft-lb
k = spring constant in lb/ft
x = spring deformation in ft
we clear k from the equation (1)
Equation (2)
We replace x = 2ft, W = 12 ft-lb in the equation (2)
Calculation of work required to stretch spring 12 ft
We replace k = 6 lb/ft and x = 12ft in the equation (1)
Answer:
L = 1.11 x m, is the length of piece of 20 cm wide Aluminum foil to make capacitor large enough to hold 52000 J of energy.
Explanation:
Solution:
Data Given:
Heat Energy = 52000 J
Dielectric Constant of the plastic Bag = 3.7 = K
Thickness = 2.6 x m =d
V = 610 volts
A = width x Length
width = 20 cm = 20 x m
Length = ?
So,
we know that,
U = 1/2 C Δ
U = 52000 J
C = ?
V = 610 volts'
So,
U = 1/2 C Δ
52000 J = (0.5) x (C) x ()
C = 0.28 F
And we also know that,
C =
E = 8.85 x
K = 3.7
A = 0.20 x L
d = 2.6 x m
Plugging in the values into the formula, we get:
0.28 =
Solving for L, we get:
L = 1.11 x m,
is the length of piece of 20 cm wide Aluminum foil to make capacitor large enough to hold 52000 J of energy.
Answer:
<h2>
r = 9.27*10^-4m</h2>
Explanation:
Given the following parameters;
Tension in the wire T = 821N
wave speed of the transverse wave v = 185m/s
density of nickel = 8.9*10³kg/m³
radius of the wire = ?
Using the relationship for finding the speed of the wave to first get the linear density;
where is the linear density
Also;
= mass m/Length L
Since mass m = density * volume
Since A = area of the wire =
Given
0.024 = 8.9*10³*3.14r²
0.024 = 27.946r²
r² = 0.024/27.964
r² = 8.6*10^-7
r =√8.6*10^-7
r = 9.27*10^-4m
Radius of the wire is 9.27*10^-4m
Answer:
the speed in -y
Explanation:
For this exercise we must use the right hand rule. The motion of a positive charge is given by.
Thumb points in the direction of speed
fingers extended in the direction of the magnetic field, + z axis
the palm in the direction of the force, as the charge is negative in the opposite direction of the force, axis + x
therefore the thumb is in the direction - y
the speed in -y
answer: transverse and longitudinal