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sergij07 [2.7K]
3 years ago
10

A car is traveling at a speed of 50 m/sec when it suddenly accelerates at a rate of 5 m/sec2. How fast will the car be going (fi

nal velocity) if it maintains that acceleration for 30 seconds?
Physics
1 answer:
NISA [10]3 years ago
5 0

Answer:

200 ms-1

Explanation:

v = u+ at

v = 50+ 5×30

v = 200 ms-1

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A car that increases its speed from 20 km/h to 100 km/h undergoes
Kamila [148]

Answer:

accelaration

Explanation:

3 0
3 years ago
The hubbles telescopes orbit is 5.6 x10 ^5 meters above earths suface. the telescope has a mass os 1.1 x10^4 kilograms. earth ex
Andru [333]
(3) 8.3 N/kg. The gravitational field strength at a point is the force per unit mass exerted on a mass placed at that point. So at the point where the Hubble telescope is, it is (9.1 x 10^4)N/(1.1 x 10^4 kg) = 8.3 N/kg

Fam
7 0
3 years ago
S A block of mass M is connected to a spring of mass m and oscillates in simple harmonic motion on a frictionless, horizontal tr
cestrela7 [59]

The kinetic energy of this block-spring when the block has a speed (v) is given by K.E = 1/2 × (M + m/3)v².

<h3>What is kinetic energy?</h3>

Kinetic energy can be defined as a form of energy that is possessed by a person due to its motion or change in speed (acceleration).

<h3>How to calculate kinetic energy?</h3>

Mathematically, kinetic energy can be calculated by using this formula:

K.E = 1/2 × mv²

Where:

  • K.E represents the kinetic energy.
  • m represents the mass.
  • v represents the speed or velocity.

Since the mass of a segment of this spring is dm = (m/l) dx, the kinetic energy for each of its segment would be given by:

dK = 1/2 × (dm)Vx²

This ultimately implies that, the kinetic energy of this block-spring when the block has a speed (v) is given by:

K.E = 1/2 × Mv² + 1/2 × ¹∫₀((x²v²/l²)m/ldx

K.E = 1/2 × (M + m/3)v².

Read more on kinetic energy here: brainly.com/question/15848455

#SPJ4

6 0
2 years ago
A ball of mass 0.250 kg and a velocity of + 5.00 m/s collides head-on with a ball of mass 0.800 kg that is initially at rest. No
Mademuasel [1]

Answer:

v_1=-2.616\ m/s

Explanation:

Given that,

Mass of ball 1, m_1=0.25\ kg

Initial speed of ball 1, u_1=5\ m/s

Mass of ball 2, m_2=0.8\ kg

Initial speed of ball 2, u_2=0 (at rest)

After the collision,

Final speed of ball 2, v_2=2.38\ m/s

Let v_2 is the final speed of ball 1.

Initial momentum of the system is :

p_i=m_1u_1+m_2u_2

p_i=0.25\times 5+0

p_i=1.25\ m/s

Final momentum of the system is :

p_f=m_1v_1+m_2v_2

p_f=0.25\times v_1+0.8\times 2.38

p_f=0.25 v_1+1.904

According the law of conservation of linear momentum :

initial momentum = final momentum

1.25=0.25 v_1+1.904

v_1=-2.616\ m/s

So, the final velocity of ball 1 is (-2.616)m/s.

8 0
3 years ago
If a 0.750M solution exerts an osmotic pressure of 22.5atm, what must be the temperature (in Kelvin) of the solution
faust18 [17]

Answer:

T = 365.58 K

Explanation:

Given that,

The concentration of solution, C = 0.750M

Osmotic pressure, P = 22.5 atm

We need to find the temperature of the solution.

The formula for the osmotic pressure is given by :

P=CRT

Where

R is gas constant, R=0.08206\ L\ atm/mol-K

T=\dfrac{P}{CR}\\\\=\dfrac{22.5}{0.75\times 0.08206}\\\\=365.58\ K

So, the temperature of the solution is 365.58 K.

5 0
3 years ago
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