Each outlier in a box plot is symbolised by a "dot". So there can be two possible answers since there are two different outliers in each end of the box plot (5 and 73): either C or D.
The line in the middle of the boxes is equal to the median. If you find the median, you can approximately determine where the middle-line is, and choose whether C or D is is best fit.
Complete question is;
Find the exact values of the six trigonometric functions 0 if the terminal side of 0 in standard position contains the points(-5,-4).
Answer:
Sin θ = -4/√41
Cos θ = -5/√41
tan θ = 4/5
Cosec θ = (√41)/-4
Sec θ = (√41)/-5
Cot θ = 5/4
Step-by-step explanation:
Now, we are given the point (-5, -4)
These are x and y points.
They will form a triangle and we know that from pythagoras theorem;
x² + y² = r²
Where r is the distance between the point and the origin
Thus;
r² = (-5)² + (-4)²
r² = 25 + 16
r = √41
So, y is the opposite side of the triangle while x is the adjacent side with r being the hypotenuse.
Thus, the trigonometric ratios are;
Sin θ = opp/hyp = -4/√41
Cos θ = adj/hyp = -5/√41
tan θ = opp/adj = -4/-5 = 4/5
Cosec θ = 1/Sin θ = 1/(-4/√41) = (√41)/-4
Sec θ = 1/cos θ = 1/(-5/√41) = (√41)/-5
Cot θ = 1/tan θ = 1/(4/5) = 5/4
The 5’s cancel each other out, so you’re just left with a on that side, meaning -3=a.
Answer:
3x times 3x times 3x times 3x + x^3 + 3x times 2x times 3x times 2x + 2x
or
x^3 + 2x^3 + 3x^6
Step-by-step explanation:
3x^4 + x^3 + 6x^2 + 2x
3x times 3x times 3x times 3x + x^3 + 6x times 6x + 2x
3x times 3x times 3x times 3x + x^3 + 3x times 2x times 3x times 2x + 2x
x^3 + 2x^3 + 3x^6
Solve v by simplifying both sides of the equation, then isolating variable
v= -5
