Complete question is;
Find the exact values of the six trigonometric functions 0 if the terminal side of 0 in standard position contains the points(-5,-4).
Answer:
Sin θ = -4/√41
Cos θ = -5/√41
tan θ = 4/5
Cosec θ = (√41)/-4
Sec θ = (√41)/-5
Cot θ = 5/4
Step-by-step explanation:
Now, we are given the point (-5, -4)
These are x and y points.
They will form a triangle and we know that from pythagoras theorem;
x² + y² = r²
Where r is the distance between the point and the origin
Thus;
r² = (-5)² + (-4)²
r² = 25 + 16
r = √41
So, y is the opposite side of the triangle while x is the adjacent side with r being the hypotenuse.
Thus, the trigonometric ratios are;
Sin θ = opp/hyp = -4/√41
Cos θ = adj/hyp = -5/√41
tan θ = opp/adj = -4/-5 = 4/5
Cosec θ = 1/Sin θ = 1/(-4/√41) = (√41)/-4
Sec θ = 1/cos θ = 1/(-5/√41) = (√41)/-5
Cot θ = 1/tan θ = 1/(4/5) = 5/4
