For each question we must apply the Pythagorean theorem and clear the value of x.
question 5
x = root (14 ^ 2 + 16 ^ 2)
x = root (452)
x = 2raiz (113)
question 6
x = root (8 ^ 2 + 15 ^ 2)
x = 17
question 7
x = root (12 ^ 2 + 12 ^ 2)
x = root (2 * (12 ^ 2))
x = 12raiz (2)
question 8
x = root (18 ^ 2 - 9 ^ 2)
x = root (243)
x = 9raiz (3)
<h3>
Hola! :D ¡te invito a recibir ayuda de un latinoamericano puto!</h3><h2><u>
_____________________________________ </u></h2><h2> 8.35x - 1.5 = 71.98</h2><h2> - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -</h2>
<u>El -1,5 qlero pasaría al otro lado positivo</u>
<h3> 8.35x = 71.98 + 1.5</h3><h2> - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -</h2>
<u>Ahora, se suma 71.98 + 1.5 = 73,48</u>
<h3> 8.35x = 73,48</h3><h2> - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -</h2>
<u>El 8.35 qlero que está multiplicando, pasa al otro lado pero dividiendo</u>
<h3> x = 73,48 ÷ 8.35</h3><h2> - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -</h2>
<u>Dividimos</u>
<h3> x = 8,8</h3><h2> - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -</h2><h2> <u>(b) 8,8</u> es la opción correcta</h2>
Answer:
x = -2 and x = 5/4
Step-by-step explanation:
The image below shows step-by-step on how to solve it.
Hope this helps! :)
Answer:
1. S.A. = 4350 cm²
2. S.A. = 864 cm²
3. S.A. = 240 cm²
4. S.A. = 224 m²
5. S.A. = 301.6 in.²
6. S.A. = 6,082.1 cm²
7. S.A. = 923.6 in.²
Step-by-step explanation:
1. Surface area of the rectangular prism = 2(LW + LH + WH)
L = 45 cm
W = 25 cm
H = 15 cm
S.A. = 2(45*25 + 45*15 + 25*15)
S.A. = 4350 m²
2. Surface area of the cube = 6a²
a = 12 cm
S.A. = 6(12²)
S.A. = 864 cm²
3. Surface area of triangular prism = bh + (s1 + s2 + s3)*H
b = 4 cm
h = 6 cm
s1 = 4 cm
s2 = 7 cm
s3 = 7 cm
H = 12 cm
Plug in the values
S.A. = 4*6 + (4 + 7 + 7)*12
S.A. = 24 + (18)*12
S.A. = 24 + 216
S.A. = 240 cm²
4. Surface area of the square based pyramid = area of the square base + 4(area of 1 triangular face)
S.A. = (8*8) + 4[(8*10)/2]
S.A. = 64 + 4(40)
S.A. = 64 + 160
S.A. = 224 cm²
5. Surface area of the cone = πrl + πr²
r = 6 in.
l = 10 in.
S.A. = π*6*10 + π*r²
S.A. = 60π + 36π
S.A. = 301.592895
S.A. = 301.6 in.² (nearest tenth)
6. Surface area of the sphere = 4πr²
r = 22 cm
S.A. = 4*π*22²
S.A. = 1,936π
S.A. = 6,082.1 cm² (nearest tenth)
7. Surface area of the cylinder = 2πrh + 2πr²
r = 7 in.
h = 14 in.
S.A. = 2*π*7*14 + 2*π*7²
S.A. = 923.6 in.² (nearest tenth)
