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SSSSS [86.1K]
3 years ago
15

It is 10 3/5 miles from Alston to Barton and 12 1/2 miles from Barton to Chester. The distance from Alston to Durbin, via Barton

and Chester, is 35 miles. How far is it from Chester to Durbin

Mathematics
1 answer:
amid [387]3 years ago
6 0

Answer:

Chester to Durbin is 11.9 miles far.

Step-by-step explanation:

Please refer to the attached figure.

Given:-

Distance from Alston to Barton=10\frac{3}{5} =\frac{50+3}{5} =\frac{53}{5}

Distance from Alston to Barton = 10.6 miles

Distance from Barton to Chester = 12\frac{1}{2} =\frac{24+1}{2} =\frac{25}{2}

Distance from Barton to Chester = 12.5 miles

Distance from Alston to Durbin = 35 miles.

To find:- Distance from Chester to Durbin = ?

Solution:-

Let Alston=A, Barton=B, Chester=C, Durbin=D.

Now from the attached figure we can see that,

A to B is the distance from Alston to Barton,

\therefore\ AB=10.6\ miles

B to C is the distance from Barton to Chester,

\therefore\ BC=12.5\ miles

A to is the distance from Alston to Durbin,

\therefore\ AD=35 miles

C to D is the distance from Chester to Durbin

\therefore We have to find Distance CD=?

Now from the attached figure we can see that,

CD=AD-AC

CD=AD-(AB+BC)

CD=35-(10.6+12.5)

CD=35-23.1

CD=11.9\ miles

As CD is the distance from Chester to Durbin,

Therefore Chester to Durbin is 11.9 miles far.

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Explain why any of the four operations placed between two terms 5 and -3 sqrt (8) will result in an irrational number
Gnoma [55]

Sum/difference:

Let

x = 5 + (-3\sqrt{8}) = 5-3\sqrt{8}

This means that

3\sqrt{8} = 5-x \iff \sqrt{8} = \dfrac{5-x}{3}

Now, assume that x is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that x was rational, which proves that the sum/difference of the two given terms was irrational

Multiplication/division:

The logic is actually the same: if we multiply the two terms we get

x = -15\sqrt{8}

if again we assume x to be rational, we have

\sqrt{8} = -\dfrac{x}{15}

But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.

7 0
3 years ago
What is the difference?<br>​
OleMash [197]

Answer:

B

Step-by-step explanation:

In the attached file

8 0
3 years ago
PLZ HELP ME HURRY PWEASE!!!!!!!!!
Anna71 [15]

Answer:

1.5.80 miles

2.9.80ft

3.56 inches

4.5.20 units

5. 13 units

6.5.40 ft

Step-by-step explanation:

⇒These questions are on the Pythagorean relationship

⇒General expression is ;

a²+b²=c² where a and b are values for the legs and c is the hypotenuse

1. Isaiah waked 3 miles north and 5 miles east.

Finding the distance from starting point we apply the equation;

a²+b²=c² where a=5 miles and b=3miles

5²+3²=c²

25+9=c²

34=c²

c=√34 = 5.80 miles

2.The ladder is leaning against the wall to form the hypotenuse side of 10 ft.The distance from the base to the ladder forms side a= 2ft. The question requires you to calculate the height b.

a²+b²=c²

2²+b²=10²

4+b²=100

b²=100-4

b=√96

b=9.80 ft

3. The television has a diagonal of 70 inches to represent side c and a height of 42 inches to represent the side a. The question requires you to find the width of  the television which represents the side b

a²+ b²=c²

42²+b²=70²

b²=70²-42²

b=√3136

c=56 inches

4. An equilateral triangle is one that has all its sides and angles equal. Here you have to introduce a perpendicular line from the apex point of the triangle to the base and get the distance a.The using the hypotenuse and the distance a, you can find the height/b.

c= 6 units and a=6/2= 3 units

a²+b²=c²     3²+ b²= 6²

9+b²=36

b²=36-9

b=√27 =5.20 units

5.In this question, you are given the height and the width of the right triangle thus apply the relationship as;

a²+b²=c²..........where a=5 and b=12

5²+12²=c²

25+144=c²⇒⇒⇒c=√169 =13 units

6. In this question, the height of the plant represents side b and the distance of the base from where the string is tied is side b.You are to find the length of the string which represents the hypotenuse side.

a²+b²=c²

5²+2²=c²

25+4=c²

29=c²

√29=c

c=5.40 ft

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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