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3 years ago

The Johnson family pays $1,320

Mathematics

1 answer:

Dominik [7]3 years ago

8 0

So you know that they pay $1320 on tax per year, but you want to know how much tax they pay per month. So we divide this number by 12 which is how many months are in one year. That gives you $110 they are spending on tax per month. Their monthly house payment is $862, so we add in the tax. $862+$110. This gives you $972 which is your final answer.

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What is 2+ 7 11/12 I need help on this one so please someone help me :)

lbvjy [14]

Answer:

= 119/12

= 9 11/12

Step-by-step explanation:

2 + 7 11/12

= 2 + 95/12

= 2 * 12 + 95/12

= 24 + 95/12

<em><u>= 119/12 = 9 11/12</u></em>

6 0

3 years ago

A recent study in a small city stated that the average age of robbery victims was 63.5 years. A random sample of 20 recent victi

Elina [12.6K]

Answer:

The p-value of the test is of 0.3219 > 0.05, which means that at $\alpha = 0.05$ , the average age is not higher than originally believed.

Step-by-step explanation:

A recent study in a small city stated that the average age of robbery victims was 63.5 years. Test if the average age higher than originally believed.

At the null hypothesis, we test that the mean is the believed mean age of 63.5 years, that is:

$H_0: \mu = 63.5$

At the alternate hypothesis, we test if this mean is higher, that is:

$H_1: \mu > 63.5$

The test statistic is:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

63.5 is tested at the null hypothesis:

This means that $\mu = 63.5$

A random sample of 20 recent victims had a mean of 63.7 years and a standard deviation of 1.9 years.

This means that $n = 20, X = 63.7, s = 1.9$

Test statistic:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{63.7 - 63.5}{\frac{1.9}{\sqrt{20}}}$

$t = 0.47$

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 63.7, which is a right-tailed test, with t = 0.47 and 20 - 1 = 19 degrees of freedom.

With the help of a calculator, this probability is of 0.3219.

The p-value of the test is of 0.3219 > 0.05, which means that at $\alpha = 0.05$ , the average age is not higher than originally believed.

5 0

3 years ago

Maggie wants to know what is 30% of $15

juin [17]

30% of $15 is $4.50,hope this helps!

6 0

4 years ago

Read 2 more answers

If someone gave me a ten dollar bill and pumped 8.81 in gas how much change do I give him? I forgot how to carry the ten over

Artist 52 [7]