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3 years ago

13

Ronald needs a morning breakfast drink that will give him at least 390 calories. Orange juice has 130 calories in 8oz. How many

ounces does he need to drink to reach his calorie goal?

1 answer:

Nitella [24]3 years ago

5 0

Answer:

24 ounces of orange juice

Step-by-step explanation:

Given-

Calories needed=390 calories

Calories in 8oz juice=130 calorie

Therefore ounces of juice=(390/130)8

=3 x 8

=24 ounces

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Write the opposite of – 1/2 explain.

mrs_skeptik [129]

The opposite of -1/2 is 1/2. If you put -1/2 in absolute value, then the answer is 1/2.

8 0

4 years ago

A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of

Ivenika [448]

The equation for the height of the rocket at time t given

$h= -16t^2+192t$

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

$h= -16t^2+192t$

$560 = -16t^2+192t$

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

$560 = -16(t^2 - 12t)$

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

$560/-16 = -16(t^2-12t)/-16$

$-35 = t^2 -12t$

Now we will move -35 to the righ side by adding 35 to both sides.

$-35+35 = t^2-12t+35$

$0 = t^2 -12t+35$

$t^2-12t+35 = 0$

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

$t^2-12t+35 =0$

$(t-5)(t-7) =0$

So by using zero product property we will get

$t-5 =0$

$t-5+5 = 0+5$

$t=5$

Also $t-7 =0$

$t-7+7 = 0+7$

$t=7$

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

$h= -16t^2+192t$

$0= -16t^2 + 192 t$

$0 = -16(t^2-12t)$

$-16(t^2-12t) = 0$

We will move -16 to the other side by dividing it to both sides.

$-16(t^2-12t)/-16 = 0/-16$

$t^2-12t = 0$

We will take out the common factor t from the left side. By taking out t we will get,

$t(t-12) = 0$

We will use zero product property now. By using that we will get,

$t = 0$

ans also $t-12 = 0$

$t-12+12 = 0+12$

$t = 12$

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0

3 years ago

A robot’s height is 1 meter 20 centimeters. How tall is the robot in millimeters?

Flura [38]

Answer:

A

Step-by-step explanation:

There are 1000 mm in one meter

and there are 10 mm in one cm

so

1000 + 20(10) = 1200mm

Therefore the answer is 1200mm

8 0

2 years ago

Read 2 more answers

Write an equation for the orbit of Saturn in the form x^2/a^2 + y^2/b^2 = 1

frozen [14]

Answer:

x²/2166784 +y²/2159989 = 1

Step-by-step explanation:

The relationship between the semi-axes and the eccentricity of an ellipse is ...

e = √(1 -b²/a²)

In order to write the desired equation we need to find 'b' from 'e' and 'a'.

__

<h3>semi-minor axis</h3>

Squaring the equation for eccentricity gives ...

e² = 1 -b²/a²

Solving for b², we have ...

b²/a² = 1 -e²

b² = a²(1 -e²)

<h3>ellipse equation</h3>

Using the given values, we find ...

b² = 1472²(1 -0.056²) = 2166784(0.996864) ≈ 2159989

The desired equation is ...

x²/2166784 +y²/2159989 = 1

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2 years ago

A plane averaged 500 mph on a trip going east but only 350 mph on the return trip. The total flying time for both directions was

Fittoniya [83]

Answer:I wish I knew

Step-by-step explanation:

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3 years ago