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4 years ago

Two types of shipping boxes are shown below.

Mathematics

1 answer:

devlian [24]4 years ago

7 0

Answer:

B. 3 square feet

Step-by-step explanation:

The formula for surface area is:

2lw+2lh+2wh

Box F's surface area is just plugging in those variables

2(3)(3)+2(3)(3)+2(3)(3)=54

Box J's surface area is the same way

2(2)(4.5)+2(2)(3)+2(4.5)(3)=57

The difference is 57-54=3

The answer is B. 3 square ft

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Find the length of the radius of the circle whose perimeter is xcm and the area is

Jobisdone [24]

$\bf \stackrel{\textit{perimeter}}{\textit{circumference}}\textit{ of a circle}\\\\ C = 2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=x \end{cases}\implies x = 2\pi r\implies \boxed{\cfrac{x}{2\pi }=r} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ A=x \end{cases}\implies x = \pi \left( \boxed{\cfrac{x}{2\pi }} \right)^2\implies x = \pi \cdot \cfrac{x^2}{2^2\pi^2}$

$\bf x = \cfrac{x^2}{4\pi }\implies 4\pi x = x^2\implies \cfrac{4\pi x}{x}=x\implies \blacktriangleright 4\pi = x\blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{since the radius is}}{r = \cfrac{x}{2\pi }}\implies r =\cfrac{4\pi }{2\pi }\implies \blacktriangleright r = 2\blacktriangleleft$

6 0

4 years ago

Read 2 more answers

PLS HELP WILL MARK AS BRAINLIEST

soldier1979 [14.2K]

Answer:

26. the y intercept is -6

27. the y intercept is 2

28. the y intercept is -3

29. I cant answer because it is cut off in the picture...

Step-by-step explanation:

These equations follow a simple formula- the slope formula

y=mx+b

In this formula:

b is the y intercept

m is the slope that is multiplied by x

hope this helps:)

please crown me brainliest!!!

3 0

3 years ago

Answer to this plz I'm so confused

Natalija [7]

Theres nothing to see on the screen

8 0

3 years ago

What are the solutions of-4(x-4) < -8

Andrew [12]

Answer:

-4x+16 < -8

Step-by-step explanation:

x*-4=-4x

4*-4=-16

-16

4 0

3 years ago

When constructing parallel lines, how can you verify the lines constructed are parallel? Check the intersecting lines with the c

Bond [772]

Answer:

Check the distance between the lines at several places with a compass to ensure they are equidistant.

Step-by-step explanation:

The distance between the parallel lines is always constant and they never intersect with each other.

So, to verify if the lines constructed are parallel, we can check the following:

Check the distance between the lines at several places with a compass to ensure they are equidistant.

6 0

4 years ago