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Artyom0805 [142]
3 years ago
15

Compute the following: 325 C1

Mathematics
2 answers:
borishaifa [10]3 years ago
8 0
If this is a combination problem, 325 choose 1, anytime you have a choose 1, the answer it the n, so 325 is the answer.
vampirchik [111]3 years ago
5 0

Answer:

{325 \choose 1}=325

Step-by-step explanation:

  Given :   {325 \choose 1}

We have to find the value of given combination.

Consider the given expression  {325 \choose 1}

We know

Given a number of subset of r elements out of  n elements is given by,

{n \choose r}=\frac{n!}{r!\left(n-r\right)!}

Comparing , we have n = 325 and r = 1

Substitute, we get,

{325 \choose 1}=\frac{325!}{1!\left(325-1\right)!}

On simplifying, we get,

{325 \choose 1}=\frac{325!}{1!\left(324\right)!}

325!=325 \times 324! substitute, we get,

{325 \choose 1}=\frac{325 \times 324!}{1!\left(324\right)!}

On simplifying, we get,

{325 \choose 1}=\frac{325}{1!}

Thus, {325 \choose 1}=325

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PLEASE HELP!!!
GalinKa [24]

Answer:

14-5i

Step-by-step explanation:

Distribute using FOIL

12+3i-8i-2i^2

i^2 = -1

12+3i-8i-2(-1)

12+3i-8i+2

Combine like terms

14-5i

4 0
3 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
Use an inequality symbol(<>_= to compare _26_54
Rina8888 [55]
26 < 54
26 is less than 54
4 0
3 years ago
Read 2 more answers
If x = 10, what is the first step you would do to answer 3x 2
Vinvika [58]

Answer:

300

Step-by-step explanation:

X^2=10×10=100

3×100=300

3 0
3 years ago
Wat is da closest answer to 3723.4 divided by 27.1
aev [14]

Answer:

It’s 137.39

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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