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Elina [12.6K]
3 years ago
12

Kind of struggling, can anyone help?

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
8 0
This should be the correct way to solve the problems. Sorry if my handwriting lokks bad.

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Sam scored 36 marks out of 60.Express the marks in percentage ​
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60%

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3 years ago a father was 3 times as old as his son, in five years time he will be twice as old as his son, what will be the sum
ivolga24 [154]

Answer: 46 years

Step-by-step explanation:

Let the father's age be x and the son's age be y, then 3 years ago:

Father = x - 3

son     = y - 3

Then , from the first statement :

x - 3 = 3 ( y - 3 )

x - 3 = 3y - 9

x     = 3y - 9 + 3

x     = 3y - 6 .......................................... equation 1

In five years time

father = x + 5

son = y + 5

Then , from the second statement

x + 5 = 2 ( y + 5 )

x + 5 = 2y + 10

x       = 2y + 10 - 5

x       = 2y + 5 ........................ equation 2

Equating equation 1 and 2 , we have

3y -6 = 2y + 5

add 6 to both sides

3y = 2y + 5 + 6

subtract 2y from both sides

3y - 2y = 11

y = 11

substitute y = 11 into equation 1 to find the value of x

x = 3y - 6

x = 3(11) - 6

x = 33 - 6

x = 27

This means that the father is presently 27 years and the son is presently 11 years.

In four years time

father = 27 + 4 = 31

son = 11 + 4      = 15

sum of their ages in four years time will be

31 + 15 = 46 years

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Step-by-step explanation:

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Plz help 1-4 r true and false questions
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1. False
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