Write an equation in slope-intercept form of the line with the parametric equations x=-4t+3 and 5t-3
1 answer:
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Answer:
x = ±2, 3 are the critical points of the given inequality.
Step-by-step explanation:
The given inequality is
To find the critical points we will equate the numerator and denominator of the inequality to zero.
For numerator,
(x - 2)(x + 2) = 0
x = ±2
For denominator,
x² - 5x + 6 = 0
x² - 3x -2x + 6 = 0
x(x - 3) -2(x - 3) = 0
(x - 3)(x - 2) = 0
x = 2, 3
Therefore, critical points of the inequality are x = ±2, 3 where the sign of the inequality will change.
Answer:
m = - 8 ± 6
Step-by-step explanation:
Given
m² + 16m - 8 = 0 ( add 8 to both sides )
m² + 16m = 8
To complete the square
add ( half the coefficient of the m- term )² to both sides
m² + 2(8)m + 64 = 8 + 64
(m + 8)² = 72 ( take the square root of both sides )
m + 8 = ± = ±
= ± 6
Subtract 8 from both sides
m = - 8 ± 6