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DerKrebs [107]
3 years ago
6

I need help with this​

Mathematics
2 answers:
Nikolay [14]3 years ago
7 0

Answer:

24.3470022334

Step-by-step explanation:

Tju [1.3M]3 years ago
4 0
I hope this helps. It really isn’t too hard. All you need to do is find the multiples of 24

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If GJ = 7 and HJ = 6, then H _____ G. Choose the relationship symbol that would make a true statement. < = >
pantera1 [17]

It would be less than. (<)

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3 years ago
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In which figure is DE BC
stepan [7]

Answer:

Given: DB = 7.2 cm, AE = 1.8 cm and EC = 5.4 cm and DE || BC.

DB

AD

=

AC

AE

[by basic proportionality theorem which states that if a line is drawn parallel to one side of a triangle the other two sides in distinct points, then the other two sides are divided in the same.

7.2

AD

=

5.4

1.8

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24

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4 0
3 years ago
What multiplies to -9 and adds to 8
Free_Kalibri [48]
9 and -1 9*-1=-9 and 9-1=8

5 0
3 years ago
If five numbers are selected at random from the set {1,2,3,...,20}, what is the probability that their minimum is larger than 5?
Zanzabum

Answer:

the probability that their minimum is larger than 5 is 0.2373

Step-by-step explanation:

For calculate the probability we need to make a división between the total ways to selected the 5 numbers and the ways to select the five numbers in which every number is larger than 5.

So the number of possibilities to select 5 numbers from 20 is:

<u>20                </u> * <u>      20         </u>*  <u>        20     </u> *<u>        20         </u>* <u>       20 </u>

First number  2nd number   3rd number  4th number   5th number

Taking into account that a number can be chosen more than once, and the order in which you select the numbers matters, for every position we have 20 options so, there are  20^{5} ways to select 5 numbers.

Then the number of possibilities in which their minimum number is larger than 5 is calculate as:

<u>15                </u> * <u>      15         </u>*  <u>           15     </u> *<u>        15          </u>* <u>       15 </u>

First number  2nd number   3rd number  4th number   5th number

This time for every option we can choose number from 6 to 20, so we have 15 numbers for every option and the total ways that satisfy the condition are  15^{5}

So the probability P can be calculate as:

P=\frac{15^{5} }{20^{5} } \\P=0.2373

Then the probability that their minimum is larger than 5 is 0.2373

7 0
3 years ago
2⁶ x⁹ y¹⁰ z/4³ x³ y¹⁰ z​
coldgirl [10]

Answer:

2

Step-by-step explanation:

5 0
3 years ago
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