<u>Answer:</u>
The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744
<u>Solution:</u>
Total number of coils = number of good coils + defective coils = 88 + 12 = 100
p(getting two good coils for two selection) = p( getting 2 good coils for first selection )
p(getting 2 good coils for second selection)
p(first selection) = p(second selection) = 
Hence, p(getting 2 good coil for two selection) = 
Answer: I think the answer is n=2
Step-by-step explanation:
Part A:
From the central limit theorem, since the number of samples is large enough (up to 30), the mean of the the mean of the average number of moths in 30 traps is
0.6.
Part B:
The standard deviation is given by the population deviation divided by the square root of the sample size.

Part C:
The probability that an approximately normally distributed data with a mean, μ, and the standard deviation, σ, with a sample size of n is greater than a number, x, given by

Thus, given that the mean is 0.6 and the standard deviation is 0.4, the probability that <span>the average number of moths in 30 traps is greater than 0.7</span> given by:
No you can't
Because in an equilateral triangle all sides and angles must be equal and for that all angles must equal 60 degrees so that their sum is 180 degrees, but a right triangle requires an angle of 90 degrees which the equilateral triangle doesn't have, so there's no such thing as an equilateral right triangle.
Answer:
n log(m)
Step-by-step explanation: