Full question:
Assume you are using the text's array-based queue and have just instantiated a queue of capacity 10. You enqueue 5 elements and then deque 2 elements. Which indices of the internal array elements hold the remaining elements? a) 0 to 2 b) 7 to 9 c) 2 to 4 d) 1 to 3
Answer and Explanation:
If you instantiate a capacity of 10 for the queue, you have the queue a capacity of not more than 10 values.
To enqueue means to add an element to the array(if it's not full, n<10)
To dequeue means to delete an element from the array or queue(if n! =0)
From the question, for example:
We create a queue of capacity 10:
Queue q(10);
We add elements/enqueue 5 elements to the queue :
q.queueEnqueue(10);
q.queueEnqueue(5);
q.queueEnqueue(8);
q.queueEnqueue(9);
q.queueEnqueue(2);
If we print this out:
q. queueDisplay()
We would get:
10, 5, 8, 9, 2
We remove elements/dequeue 2 elements from the queue :
q. queuedequeue();
q. queuedequeue();
We print it out:
q. queueDisplay()
8 ,9, 2
We observe that deletion/dequeue starts from the front/first index.
We are left with indices 2, 3, 4 or 2 to 4
Note: the above methods/ functions and objects used are merely for example purposes. The queue uses a floating front design approach.
Answer:
Depending on the error message which Alice get but what could have gone wrong is perhaps firewall issue.
Explanation:
There are lots of probable reason why Alice could not access her files during the weekend but below are some common reasons:
Firewall issue: Maybe Alice has her firewall turned on unknowingly as it is known that firewall do block such types of connection except it is explicitly allowed from the firewall settings. Another issue might be that, Alice ISP uses firewall.
FTP programs Setting: Perhaps there is a settings which Alice has not activated in the FTP program that she is using.
Why do companies use online collaborative productivity software? Companies use online collaborative productivity software to allow employees to share document such as reports or spreadsheets and make edits or comments.
Answer:
Number of fragments is 3
Explanation:
The maximum size of data field in each fragment = 4468 - 20(IP Header)
= 4448 bytes
Hence, the number of required fragment = (10000 - 20)/4448
= 3
Fragment 1
Id = 218
offset = 0
total length = 4468 bytes
flag = 1
Fragment 2
Id = 218
offset = 556
total length = 4468 bytes
flag = 1
Fragment 3
Id = 218
offset = 1112
total length = 1144 bytes
flag = 0
Answer:
#include <bits/stdc++.h>
using namespace std;
int main() {
string email,username,host;//strings to store email,username,hostname..
cout<<"Enter the email address "<<endl;
cin>>email;//taking input of email address..
bool flag=1;
for(int i=0;i<email.length();i++)//iterating over the string email..
{
if(email[i]=='@')//if @ symbol is encountered make flag 0 skip this iteration.
{
flag=0;
continue;
}
if(flag==1)//add to username if flag is 1.
{
username+=email[i];
}
else//add tom host..
host+=email[i];
}
cout<<"The username is "<<username<<endl<<"The host name is "<<host;//printing the username and hostname..
return 0;
}
Explanation:
I have taken three strings to store the email address entered by user ,username and host to store username and host name respectively.Then I am iterating over the string email if @ is encountered then skip that iteration before that keep adding characters to username string and after that keep adding characters to host.
