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Oksanka [162]
4 years ago
8

Due largely to the prevalence of reading them on screens rather than in​ print, the body text of most contemporary documents now

use​ a(n) _________ typeface.
Computers and Technology
1 answer:
Stella [2.4K]4 years ago
4 0
.The answer is <span>sans serif. </span>Utilize sans serif textual styles in light of the fact that the close uniform width of the strokes keeps the text style intelligible when lessened in determination or diminished in text dimension. Sans serif textual styles are more clear from more distant away, which is the reason they are useful for blurbs and slides, especially the titles and headers.
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1. Write a program that asks the user to enter a string. The program should then print the following: (a) The total number of ch
Kazeer [188]

Answer:

s = input("Enter a string: ")

print(len(s))

print(s*10)

print(s[0])

print(s[:3])

print(s[len(s)-3:])

print(s[::-1])

if len(s) >= 7:

   print(s[6])

else:

   print("The string is not long enough")

print(s[1:len(s)-1])

print(s.upper())

print(s.replace("a", "e"))

Explanation:

*The code is in Python.

Ask the user to enter a string

Use len method to get the total number of characters

Use "*" to repeat 10 times

Use index, 0,  to get first character

Use slicing to get first three characters

Use slicing to get last three characters

Use slicing to get it in backwards

Check if the length is greater than or equal to 7. If it is, use index, 6. Otherwise, print a message.

Use slicing to remove first and last characters

Use upper method to get it in all caps

Use replace method to replace the "a" with the "e"

6 0
4 years ago
python If the checksum is 10, the last digit is denoted as X according to the ISBN-10 convention. Write a program that prompts t
aksik [14]

Answer:

PYTHON CODE:

str = input("Enter the first 9 digits of an ISBN-10 as a string : ") # user input

i = 1

checksum = 0 # for total sum

while i < 10:

c = int(str[i - 1]) # getting every digit of the ISBN

c = c * i

checksum += c

i=i+1

checksum=checksum % 11 # getting the last digit of ISBN

ch=checksum

if checksum==10: # if the last digit is 10 then change it to X

ch="X"

print("The Complete 10-Digit ISBN is : ",end="")

print(str,end="") # displaying the 9 digit of ISBN

print(ch) # appending the last digit of ISBN

Explanation:

3 0
3 years ago
The faster alcohol is consumed, the faster it reaches the __________.
Anni [7]
The faster it reaches the bloodstream

6 0
3 years ago
Read 2 more answers
Write a program that reads the contents of the two files into two separate lists. The user should be able to enter a boy’s name,
insens350 [35]

Answer:

Check Explanation.

Explanation:

A programming language is used by engineers, technologists, scientists or someone that learnt about programming languages and they use these programming languages to give instructions to a system. There are many types for instance, c++, python, Java and many more.

So, the solution to the question above is given below;

#define the lists

boyNames=[]

girlNames=[]

#open the text file BoyNames.txt

with open('BoyNames.txt','r') as rd_b_fl:

boyNames=rd_b_fl.readlines()

boyNames=[name.strip().lower() for name in boyNames]

#open the text file GirlNames.txt

with open('GirlNames.txt','r') as rd_b_fl:

girlNames=rd_b_fl.readlines()

girlNames=[name.strip().lower() for name in girlNames]

#print the message to prompt for name

print('Enter a name to see if it is a popular girls or boys name.')

while True:

#prompt and read the name

name=input('\nEnter a name to check, or \"stop\" to stop: ').lower()

# if the input is stop, then exit from the program

if name=='stop':

break

# If the girl name exits in the file,then return 1

g_count=girlNames.count(name)

# if return value greater than 0, then print message

if g_count>0:

print(name.title()+" is a popular girls name and is ranked "

+str(girlNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular girls name")

## If the boy name exits in the file,then return 1

b_count=boyNames.count(name)

if b_count>0:

print(name.title()+" is a popular boys name and is ranked "

+str(boyNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular boys name")

3 0
3 years ago
Explain three causes of repetitive strain injury (RSI)​
Tpy6a [65]
1. Typing on a computer for too long
2. Using a mouse for long periods
3. Holding the mouse incorrectly
Or 4. Working in a cramped workspace
4 0
3 years ago
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