Ask question

Ask question

All categories

3 years ago

10

Three pounds of lawn seed covers 1800 square feet. How many 4 pound bags are needed to cover 8400 square feet?

1 answer:

g100num [7]3 years ago

7 0

1800 ft² = 3 pounds

[divide by 3 through]
1800 ÷ 3 = 3 ÷ 3
600ft² = 1 pound

[8400 ÷ 600 = 14; so multiply by 14 through]
600 x 14 = 1 x 14
8400ft² = 14 pounds

we need 14 pounds to cover 8400 square feet.

[Find number of 4 pounds bags needed]
14 ÷ 4 = 3.5
So we need to use 4 bags of 14 pounds of lawn seeds.

You might be interested in

Help what is the value of X

EastWind [94]

I hope this helps. Since there are verticale angles that’s why I added another x.

5 0

3 years ago

Plz help its 7th grade distributive proprty

Marat540 [252]

Answer:

a = 3.9

Step-by-step explanation:

Isolate the varible by dividing each side by factors that don't contain the variable.

5 0

3 years ago

Read 2 more answers

ANSWER ASAP<br> THANKS<br> ...............

mylen [45]

Answer:

250

Step-by-step explanation:

5*5=25

25*10=250

+$++$$+$

6 0

3 years ago

(6+2) +5 = 6+ (2+5)<br> State the property described each problem

Tanzania [10]

Answer:

Associative property - addition

Step-by-step explanation:

When three or more numbers are added, the sum is the same regardless of the way in which the numbers are grouped.

(6+2) + 5 = 6 + (2+5)

8 + 5 = 6 + 7

13 = 13

7 0

3 years ago

Haya la integral de xarcsenx/((1-x^2)^1/2). Utiliza la sustitución de t= arcsenx

ikadub [295]

Answer:

<em>Explicación más abajo</em>

Step-by-step explanation:

Integración Indefinida

La integral

$I=\int \dfrac{x .arcsen\left(x\right)}{\sqrt{1-x^2}}$

Se resuelve con el cambio de variables:

t=arcsen(x)

Una vez hechos los cambios, la integral se resuelve en función de t:

$I=sen(t)-t.cos(t)+C$

Hay que devolver los cambios para mostrarla en función de x.

El cambio de variables también se puede escribir:

x=sen(t)

Recordando que

$cos(t)=\sqrt{1-sen^2(t)}$

Entonces:

$cos(t)=\sqrt{1-x^2}$

Devolviendo los cambios:

$I=sen(t)-t.cos(t)+C=x-arcsen(x)\sqrt{1-x^2}+C$

Es la respuesta correcta

7 0

3 years ago