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3 years ago

What is the average rate of change of y with respect to x over the interval [-3, 4] for the function y = 2x + 2

Mathematics

1 answer:

Ksenya-84 [330]3 years ago

7 0

Answer:

y = 2x + 10

Step-by-step explanation:

y1 = 4

x1 = -3

slope,m = 2

y - y1 = m(x - x1)

y - 4 = 2(x + 3)

y - 4 = 2x + 6

y = 2x + 10

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Simplify by dividing negative three over eight ÷ five over nine . (5 points)

Marysya12 [62]

Answer:

A.) negative twenty-seven over forty

Step-by-step explanation:

Screenshot below will explain the answer

8 0

3 years ago

Use the Distributive Property to write each expression as an equivalent algebraic expression. (7 + a)3 Question 4 options: 3(7a)

AysviL [449]

Answer:

(B)21+3a

Step-by-step explanation:

An expression is said to be distributive when:

$(a+b)c=a \cdot c+b \cdot c$

Given the algebraic expression: (7 + a)3

Applying the distributive property

$(7 + a)3 = 7 \cdot 3+a \cdot 3\\=21+3a$

An equivalent expression is 21+3a.

The correct option is B

5 0

3 years ago

Change 3/11 to a decimal

inysia [295]

To change a fraction to a decimal , you just divide the number on top by the number on the bottom.
So to change 3/11 to a decimal you divide 3 by 11 and you get 0.272727
= 3/11

= 3 ÷ 11

<span>= 0.272727
</span>
you can round this to 0.273

6 0

3 years ago

Read 2 more answers

In this exercise, consider a particle moving on a circular path of radius b described by r(t) = b cos(ωt)i + b sin(ωt)j, where ω

Bingel [31]

Answer:

Acceleration of the particle = $bw^{2}$

Step-by-step explanation:

We are given the position vector of a particle moving in a circle of radius b units.

r(t) = b cos(ωt)i + b sin(ωt)j

Velocity , v = $\frac{dr}{dt}$ = -bω sin(ωt)i + bω cos(ωt)j

The magnitude of velocity, v = $\sqrt{v_x^{2} +v_y^{2} }$

Squaring both sides,

$v^{2} = b^{2} w^{2}(sin^{2}(wt)+cos^{2}(wt))$

Since $sin^{2}(wt)+cos^{2}(wt))$ = 1

$v^{2} = b^{2}w^{2}$

The acceleration towards the centre is called the centripetal acceleration and is given by

a = $\frac{v^{2} }{r}$

a = $\frac{b^{2}w^{2}}{b}$

a = $bw^{2}$

3 0

3 years ago

Marcus has 2 3/5 gallon of blue paint.He will use 7/10 of the paint for his room.how much blue paint will Marcus use for his roo

yarga [219]

Answer:

1.82 gallon or 6.9 litres

Step-by-step explanation:

Given

Gallon of blue paint= 2 3/5 = (5*2+3)/5 = 13/5 gallon

Fraction of paint used in painting the room = 7/10 of paint available

= 7/10 * 13/5 =91/50 gallon

= 1 41/50 gallon = 1.82 gallon

**converting gallon into litres

one gallon is equal to 3.79 litres

hence 91/50 gallon = 91/50*3.79 litres = 6.9 litres

8 0

3 years ago