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GuDViN [60]
4 years ago
7

A rectangle has a perimeter of 32 in. find the length and width of the rectangle under which the area is the largest. follow the

steps: (a) let the width to be x and the length to be y , then the quantity to be maximized is (expressed as a function of both x
Mathematics
1 answer:
Dafna1 [17]4 years ago
5 0
Let width and length be x and y respectively.
Perimeter (32in) =2x+2y=> 16=x+y => y=16-x
Area, A = xy = x(16-x) = 16x-x^2
The function to maximize is area: A=16 x-x^2
For maximum area, the first derivative of A =0 => A'=16-2x =0
Solving for x: 16-2x=0 =>2x=16 => x=8 in
And therefore, y=16-8 = 8 in
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Answer:

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Step-by-step explanation:

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The last table shows a decidedly downward trend, so will have a strong negative correlation.

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<em>Comment on answer choices</em>

The order of answer presentation may vary, so "D" may not be the answer to a different instance of this question.

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Korolek [52]

Answer:

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Step-by-step explanation:

Simplifying

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Reorder the terms:

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Solving for variable 'x'.

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