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GuDViN [60]
4 years ago
7

A rectangle has a perimeter of 32 in. find the length and width of the rectangle under which the area is the largest. follow the

steps: (a) let the width to be x and the length to be y , then the quantity to be maximized is (expressed as a function of both x
Mathematics
1 answer:
Dafna1 [17]4 years ago
5 0
Let width and length be x and y respectively.
Perimeter (32in) =2x+2y=> 16=x+y => y=16-x
Area, A = xy = x(16-x) = 16x-x^2
The function to maximize is area: A=16 x-x^2
For maximum area, the first derivative of A =0 => A'=16-2x =0
Solving for x: 16-2x=0 =>2x=16 => x=8 in
And therefore, y=16-8 = 8 in
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The solution to the problem is shown below:
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3 years ago
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The triangle presented in the image has 2 axes of symmetry because it is only possible to divide it 2 times.

<h3>What are axes of symmetry?</h3>

The axes of symmetry are a concept of geometry that are classified into two groups:

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  • The axis of axial symmetry: This is the symmetry around an axis, it is a point of translation and rotation in which all the semi-planes taken from a certain perpendicular bisector have identical characteristics.

According to the above, it can be inferred that the rectangle presented in the image has only two axes of symmetry.

Learn more about symmetry in: brainly.com/question/17759737

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