DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
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Congruent shape</h3>
Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.
Given that DE = AB and BC = EF.
In right triangle DEF, using Pythagoras:
DF² = DE² + EF²
Also, In right triangle ABC, using Pythagoras:
AC² = AB² + BC²
But DE = AB and EF = BC, hence:
AC² = DE² + EF²
AC² = DF²
Taking square root of both sides, hence:
AC = DF
Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
Find out more on Congruent shape at: brainly.com/question/11329400
Can you give some specifics so I can answer your question please?
10(length) by 6.5(width). 6.5×2=13, 13-3=10
9514 1404 393
Answer:
h(0) = 10
h(4) = 16
Step-by-step explanation:
The second part of the function definition applies when x=0.
h(x) = 2x^2 -3x +10
h(0) = 0 + 0 + 10 = 10
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The third part of the function definition applies when x=4.
h(4) = 2^4 = 16
Since people read newspapers for a average of 364 minutes for a week, which is 7 days, you must divide 364 by 7. After you figure out how much they read per day multiply that by three to get your final result.
