Fifth root of thirteen

1 answer:

oee [108]3 years ago

3 0

Answer:

1.67027765233

this is the answer mate

You might be interested in

sleet_krkn [62]

Answer:

29, 26, 21, 14, 5

Step-by-step explanation:

To find the first 5 terms, substitute n = 1, 2, 3, 4, 5 into the n th term formula.

30 - 1² = 30 - 1 = 29

30 - 2² = 30 - 4 = 26

30 - 3² = 30 - 9 = 21

30 - 4² = 30 - 16 = 14

30 - 5² = 30 - 25 = 5

The first 5 terms are 29, 26, 21, 14, 5

6 0

3 years ago

vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be $\mathbf{ax^{2}+bx+c=0}$ where x is the variable.

Completing the square method is as follows:

send the constant term to other side of equal $\mathbf{ax^{2}+bx=-c}$
divide the whole equation be coefficient of $\mathbf{x^{2}}$ , this will give $\mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}$
add $\mathbf{(\frac{b}{2a})^{2}}$ to both side of equality $\mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}$
Make one fraction on the right side and compress the expression on the left side $\mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}$
rearrange the terms will give the vertex form of standard quadratic equation $\mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}$