Question

The solution to a system of linear equations is (-3,-3). Which system of linear equations has this point as its solution?

Answer 1

Answer:

Option c) is correct.

That is x-5y=12 and 3x+2y=-15 are the system of linear equations satisfies the point (-3,3) so this is the  solution.

Step-by-step explanation:

To verify that which system of linear equations having the solution (-3,-3)

Let  $x-5y=12\hfill (1)$

and $3x+2y=-15\hfill (2)$

To solve it we have to use elimination method

First multiply the equation(1) into 3 we get

$3x-15y=36\hfill (3)$

Now subtracting the equations (2)and (3) the signs may vary in the second equation we get

$3x-15y=36$

$-3x-2y=+15$

________________

$-17y=51$

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$y=-\frac{51}{17}$

$y=-3$

Now substitue the value y=-3 in equation (1) we get

$x-5y=12$

$x-5(-3)=12$

$x=12-15$

Therefore x=-3

Therefore the solution is (-3,-3)

Therefore Option c) is correct.

That is x-5y=12 and 3x+2y=-15 are the system of linear equations satisfies the point (-3,3) so  the solution is (-3,-3).