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3 years ago

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if you could generate energy by fusing the hydrogen in solution a, how much of the solution would you need to generate the elect

rical energy used daily in a certain home? energy released by fusion of hydrogen in 1 liter of solution A = 7.6*10^10 Electrical energy used daily in a certain family home = 3*10^4

1 answer:

iogann1982 [59]3 years ago

4 0

Answer:

We know that:

Energy released by fusion of hydrogen in 1 liter of solution A = 7.6x10^10 J

Energy used daily in a certain family home = 3x10^4 J

(you did not write the units, so i suppose that are the same in both cases)

Then, if x is the number of liters of solution A used, the energy produced will be:

E(x) = x*7.6x10^10 J

And we want this equal to 3x10^4

then:

E(x) = x*7.6x10^10 J = 3x10^4 j

now we solve this for x.

x = (3x10^4 j)/(7.6x10^10 j) = 3.9x10^-7

Then you need to use 3.9x10^-7 L of solution a.

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Suppose the scale factor you will use to enlarge the map is 5:1. What is the approximate area of the park in your enlarged drawi

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Answer:

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Step-by-step explanation:

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3 years ago

Calculate the value of the following determinants: | 1 -1 3 2 5 0 -3 1 2 | and | -1 -8 2 9 1 0 4 1 2 |

vitfil [10]

Answer:

1) The determinant = 65

2) The determinant = 152

Step-by-step explanation:

Let us show how to find the determinant of a matrix

You can find the determinant of this Matrix $\left[\begin{array}{ccc}a&b&c\\d&e&f\\g&m&n\end{array}\right]$

by using this rule

Determinant = a(en - fm) - b(dn - fg) + c(dm - eg)

Let us use this rule with the given matrices

1)

$\left[\begin{array}{ccc}1&-1&3\\2&5&0\\-3&1&2\end{array}\right]$

The determinand = 1[(5)(2) - (0)(1)] - (-1)[(2)(2) - (0)(-3)] + 3[(2)(1) - 5(-3)]

= 1[10 - 0] - (-1)[4 - 0] + 3[2 - (-15)]

= 1[10] + 1[4] + 3[2+15]

= 10 + 4 + 3[17]

= 10 + 4 + 51

= 65

The determinant = 65

Let us do the second one

2)

$\left[\begin{array}{ccc}-1&-8&2\\9&1&0\\4&1&2\end{array}\right]$

The determinand = -1[(1)(2) - (0)(1)] - (-8)[(9)(2) - (0)(4)] + 2[(9)(1) - 1(4)]

= -1[2 - 0] - (-8)[18 - 0] + 2[9 - 4]

= -1[2] + 8[18] + 2[5]

= -2 + 144 + 10

= 152

The determinant = 152

6 0

3 years ago

What is the axis of symmetry for f(x) = 2x2 − 8x 8? x = −2 x = −3 x = 3 x = 2

Tatiana [17]

<span>The first part of the quadratic formula, x = - b/2a, is the equation of the axis of symmetry, and the x-coordinate of the vertex. </span>

<span>In standard form: - 2x² + 8x - 5 = 0, a = - 2, b = 8, c = - 5 </span>

<span>The axis of symmetry: x = - 8/2(- 2) = - 8/- 4 = 2 </span>

<span>Go back and solve for y to find the y-coordinate of the vertex. </span>

<span>y = - 2(2)² + 8(2) - 5 </span>

<span>y = - 2(4) + 16 - 5 </span>

<span>y = - 8 + 16 - 5 </span>

<span>y = 3 </span>

<span>Vertex is (2, 3)</span>

7 0

3 years ago

Read 2 more answers

Solve the equation below by factoring

MA_775_DIABLO [31]

Answer:

The first one is n=4,-1

Second one in exact form

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Second one in decimal form

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3 years ago

Find the missing measure for a right circular cone given the following information. Find V if r = 2 and L.A. = 12. (16/3)√2 16√2

aksik [14]

Volume of cone is given by formula

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We are already given r =2, so we need to find h and then we can find volume

So missing meausre is height here ------------------------------------------------------------------------------

To find h we will use lateral area = $12\pi$ given

Formula for lateral area of cone is $\pi r\sqrt{r^{2}+ h^{2}}$

so we have $12 = \pi r\sqrt{r^{2}+ h^{2}}$

Now plug r as 2 in this equation

$12 \pi = \pi (2)\sqrt{2^{2}+ h^{2}}$

Now solve for h as shown and get h by itself

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$6^{2} = \sqrt{4+h^{2}} ^{2}$

$36} = 4+h^{2}$ $36 - 4 = 4+h^{2} -4$

$32 = h^{2}$ $\sqrt{32} = \sqrt{h^{2}}$

$\sqrt{16 \times 2} = h$ $\sqrt{16} \times \sqrt{2} = h$

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$V = \frac{\pi r^{2}h}{3}$

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$V = \frac{16 \pi \sqrt{2}}{3}$

so choice (1) is right answer

$(1) \frac{16 \sqrt{2}\pi}{3}$

correct answer --------------------------------------------------------------------------------------------------

$(2) 16 \sqrt{2} \pi$

incorrect answer as correct volume answer we got as $\frac{16 \sqrt{2}\pi}{3}$ --------------------------------------------------------------------------------------------------

$(3) 4 \sqrt{38} \pi$

incorrect answer as correct volume answer we got as $\frac{16 \sqrt{2}\pi}{3}$ --------------------------------------------------------------------------------------------------------

6 0

3 years ago

Read 2 more answers