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2 years ago

What is m angle A B E?

Mathematics

1 answer:

sattari [20]2 years ago

6 0

Answer:

∠ABE = 60°
∠DBE = 40°
∠FBA = 47°
y = 2

Step-by-step explanation:

The various markings tell you that ...

GH = GI

5x -10 = 3x

2x = 10

x = 5

and

∠ABD ≅ ∠DBC

10y° = (8y+4)°

2y = 4

y = 2

The markings on GH and GI tell you that ΔGBI ≅ ΔGBH, so ...

∠CBE ≅ ∠DBC ≅ ∠ABD = 10y° = 20°

A) m∠ABE = 60° . . . matches choice D

B) m∠DBE = 40° . . . matches choice C

C) m∠FBA = 7(5) +6(2) = 35 +12 = 47 . . . matches choice C

D) The value of y is 2. . . . matches choice A

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3 years ago

A student pushes a 51.5 kilogram bookshelf across a smooth floor with a net force of 67 N.

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The acceleration of the bookshelf is equal to 1.30 $m/s^2$

<u>Given the following data:</u>

Mass of bookshelf = 51.5 kilogram

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To determine the acceleration of the bookshelf, we would apply Newton's Second Law of Motion:

Newton's Second Law of Motion states that the acceleration of an object is directly proportional to the net force acting on the object while being inversely proportional to its mass.

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Read more on net force here: brainly.com/question/1121817

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2 years ago

Determine the Value of x,y and z.

Aleksandr-060686 [28]

Answer:

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Step-by-step explanation:

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3 years ago

Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an

Mashutka [201]

Answer:

$\sqrt\frac{387}{20}$

Step-by-step explanation:

$Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx$

$y=\dfrac{3}{5}x^{\frac{5}{3}}- \dfrac{3}{4}x^{\frac{1}{3}}+6$

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$1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})$

$=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}$

For the Interval $1\leq x\leq 8$

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Using T1-Calculator

$=\sqrt\frac{387}{20}$

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3 years ago

Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution. At Meadowbrook Hospital, the mean we

Marina86 [1]

Answer:

Required Probability = 0.1283 .

Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N( $\mu = 7 lbs , \sigma^{2} = 0.875^{2} lbs$ )

The standard normal z distribution is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean weight

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Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{7.5-7}{\frac{0.875}{\sqrt{4} } }$ ) = P(Z > 1.1428) = 0.1283 (using z% table)

Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .

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3 years ago