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soldier1979 [14.2K]
3 years ago
13

Choose the best graph that represents the linear equation: 6x = y + 8

Mathematics
1 answer:
Agata [3.3K]3 years ago
8 0

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

y = mx + b

Where:

m: It is the slope

b: It is the cut point with the y axis

We have the following equation:

6x = y + 8\\y = 6x-8

Thus, the cut point with the y axis is -8. Therefore, we discard options C and B.

It is observed that the slope is positive so the correct graph is option B.

Answer:

Option B

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We need to optimize f(x, y, z) = x + 2y subject to the constraints g(x, y, z) = x + y + z = 8 and h(x, y, z) = y2 + z2 = 4. To f
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The Lagrangian is

L(x,y,z,\lambda,\mu)=x+2y+\lambda(x+y+z-8)+\mu(y^2+z^2-4)

with critical points where the partial derivatives vanish:

L_x=1+\lambda=0\implies\lambda=-1

L_y=2+\lambda+2\mu y=0\implies\mu=-\dfrac1{2y}

L_z=\lambda+2\mu z=0\implies\mu=\dfrac1{2z}

L_\lambda=x+y+z-8=0

L_\mu=y^2+z^2-4=0

The second and third equations tell us z=-y, so that in the last equation we find

y^2+(-y)^2=2y^2=4\implies y=\pm\sqrt2\implies z=\mp\sqrt2

and from the fourth equation we get

x+y+z=x=8

So we have two critical points, (8,\sqrt2,-\sqrt2) and (8,-\sqrt2,\sqrt2), which give respective extreme values of f(8,\sqrt2,-\sqrt2)=8+2\sqrt2 (maximum) and f(8,-\sqrt2,\sqrt2)=8-2\sqrt2 (minimum).

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How do you find The area of a composite shape
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Step-by-step explanatiArea of Composite Shapes. Composite shapes are shapes that have a combination of 2-D shapes. To find the area of composite shapes you just need to break down the shape into individual pieces and calculate their separate pieces then add them back together again to find a total areaon:

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In a term,it’s factor which is a number in front of a variable
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Answer: Coefficient

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5.53 An inventory study determines that, on average, demands for a particular item at a warehouse are made 5 times per day. What
Licemer1 [7]

Answer:

a) 38.4% probability that on a given day this item is requested more than 5 times.

b) 0.67% probability that on a given day this item is not requested at all.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

An inventory study determines that, on average, demands for a particular item at a warehouse are made 5 times per day.

This means that \mu = 5

What is the probability that on a given day this item is requested

(a) more than 5 times?

Either it is requested 5 times or less, or it is requested more than 5 times. The sum of the probabilities of these events is decimal 1. So

P(X \leq 5) + P(X > 5) = 1

We want P(X > 5). So

P(X > 5) = 1 - P(X \leq 5)

In which

P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-5}*(5)^{0}}{(0)!} = 0.0067

P(X = 1) = \frac{e^{-5}*(5)^{1}}{(1)!} = 0.0337

P(X = 2) = \frac{e^{-5}*(5)^{2}}{(2)!} = 0.0842

P(X = 3) = \frac{e^{-5}*(5)^{3}}{(3)!} = 0.1404

P(X = 4) = \frac{e^{-5}*(5)^{4}}{(4)!} = 0.1755

P(X = 5) = \frac{e^{-5}*(5)^{5}}{(5)!} = 0.1755

P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0067 + 0.0337 + 0.0842 + 0.1404 + 0.1755 + 0.1755 = 0.616

P(X > 5) = 1 - P(X \leq 5) = 1 - 0.616 = 0.384

38.4% probability that on a given day this item is requested more than 5 times.

(b) not at all?

P(X = 0) = \frac{e^{-5}*(5)^{0}}{(0)!} = 0.0067

0.67% probability that on a given day this item is not requested at all.

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A sum of money at simple interest doubles itself in 10 years .Find the rate percent per annum​
tamaranim1 [39]
So rate per annum = 10%.



Mark brainliest please


Hope this helps you
7 0
3 years ago
Read 2 more answers
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