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blagie [28]
3 years ago
12

A theater wants 2000$ and children’s tickets cost 5$ and adult tickets cost 10$.What is one combination of children and adult ti

ckets that will make 2000$
Mathematics
2 answers:
marusya05 [52]3 years ago
6 0

Answer: a combination of 75 adult tickets and 250 student tickets would make $2000

Step-by-step explanation:

A theater wants 2000$ and children’s tickets cost 5$ and adult tickets cost 10$. To find a combination of children and adult tickets that will make 2000$, we would assume a value for either the number of student tickets or adult tickets and assume a variable for the other.

Assuming 250 student tickets and x adult tickets were sold. Therefore,

250 × 5 + 10x = 2000

1250 + 10x = 2000

10x = 2000 - 1250 = 750

x = 750/10 = 75

velikii [3]3 years ago
4 0

Answer:

100 adults and 200 children

Step-by-step explanation:

$10 × 100 = $1000

$5 × 200= $1000

$1000 + $ 1000 = $ 2000

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The answer is the one that is $42.  It is the lowest cost for the amount of flannel you get and the quality.  
8 0
2 years ago
Monica has $20. She needs to buy a gallon of milk that costs $2.50. She also wants to buy yogurt, which costs $1.20 a cup. What
Kitty [74]

We are given : Cost of a gallon of milk = $2.50.

Cost of a cup of yogurt = $1.20.

Total money Monica has = $20.

Number of cups of yogurt Monica can buy = x.

And inequality made is also correct

1.20x + 2.5 ≤ 20.

Now, we need to solve it for x.

Subtracting 2.5 from both sides, we get

1.20x + 2.5 -2.5 ≤ 20 - 2.5.

1.20x ≤ 17.5

Dividing both sides by 1.20, we get

1.20x/1.20 ≤ 17.5/1.20.

x ≤ 14.5833...

Because it's less than 15, so final answer is : 14 is  greatest number of cups of yogurt Monica can buy.



3 0
3 years ago
Read 2 more answers
Pleaseee helpppp:)))
matrenka [14]

Answer:

<h2><em><u>Option</u></em><em><u> </u></em><em><u>B</u></em><em><u>:</u></em></h2><h3><em><u>112</u></em><em><u> </u></em><em><u>families</u></em><em><u> </u></em></h3>

Step-by-step explanation:

<em><u>Given</u></em><em><u>,</u></em>

No. of families = 75

Out of 75 no. of families had cars = 42

Out of 1, no. of families can have cars

=  \frac{42}{75}

<em><u>Therefore</u></em><em><u>, </u></em>

Out of 200 families, no. of families had cars

= 200 \times  \frac{42}{75}

=200 \times   \frac{14}{25}

= 8 × 14

= 112

<em><u>Hence</u></em><em><u>, </u></em>

<em><u>option</u></em><em><u> </u></em><em><u>B</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>correct</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>112</u></em><em><u> </u></em><em><u>families</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>cars</u></em><em><u> </u></em><em><u>out</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>200</u></em><em><u> </u></em><em><u>families</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

5 0
2 years ago
What is the equation of a vertical ellipse with a major axis= 20 and a minor axis = 14?​
Sunny_sXe [5.5K]

\bold{\text{Answer:  b.}\quad \dfrac{y^2}{100}+\dfrac{x^2}{49}=1}

<u>Step-by-step explanation:</u>

The ellipse is vertical so y has the biggest radius.

Major axis (y) = 20 so the y-radius is 20/2 = 10

Minor axis (x) = 14 so the x-radius is 14/2 = 7

The equation of an ellipse is:   \dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1   where

  • (h, k) is the center of the ellipse
  • a is the x-radius
  • b is the y-radius

Given: a = 7, b = 10

Assume: (h, k) = (0, 0)

\dfrac{(x-0)^2}{7^2}+\dfrac{(y-0)^2}{10^2}=1\\\\\\\dfrac{x^2}{49}+\dfrac{y^2}{100}=1\\\\\\\longrightarrow \dfrac{y^2}{100}+\dfrac{x^2}{49}=1

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2 years ago
I am a product one of my factors is 9 the sum of my two factors is 13 what number am i
lesya692 [45]
If 1 of ur factors is 9...and the sum of ur factors is 13....then ur other factor is (13 - 9) = 4

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