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blagie [28]
3 years ago
12

A theater wants 2000$ and children’s tickets cost 5$ and adult tickets cost 10$.What is one combination of children and adult ti

ckets that will make 2000$
Mathematics
2 answers:
marusya05 [52]3 years ago
6 0

Answer: a combination of 75 adult tickets and 250 student tickets would make $2000

Step-by-step explanation:

A theater wants 2000$ and children’s tickets cost 5$ and adult tickets cost 10$. To find a combination of children and adult tickets that will make 2000$, we would assume a value for either the number of student tickets or adult tickets and assume a variable for the other.

Assuming 250 student tickets and x adult tickets were sold. Therefore,

250 × 5 + 10x = 2000

1250 + 10x = 2000

10x = 2000 - 1250 = 750

x = 750/10 = 75

velikii [3]3 years ago
4 0

Answer:

100 adults and 200 children

Step-by-step explanation:

$10 × 100 = $1000

$5 × 200= $1000

$1000 + $ 1000 = $ 2000

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Lubov Fominskaja [6]

<u>Answer:</u>

<u>For a:</u> The probability of getting a red or blue ball is 0.48

<u>For b:</u> The probability of getting a white, blue or orange ball is 0.81

<u>For c:</u> The probability of getting neither white or orange ball is 0.48

<u>Step-by-step explanation:</u>

Probability is defined as the extent to which an event is likely to occurs. It is measured by the ratio of the favorable outcomes to the total number of possible outcomes.

\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of favorable outcomes}}     .......(1)

We are given:

Number of red balls in a box = 12

Number of white balls in a box = 18

Number of blue balls in a box = 19

Number of orange balls in a box = 15

Total balls in a box = [12 + 18 + 19 + 15] = 64

  • <u>For a:</u>

Number of favorable outcomes (ball must be red or blue) = [12 + 19] = 31

Total number of outcomes = 64

Putting values in equation 1, we get:

\text{Probability of getting a red or blue ball}=\frac{31}{64}=0.48

  • <u>For b:</u>

Number of favorable outcomes (ball must be white or blue or orange) = [18 + 19 + 15] = 52

Total number of outcomes = 64

Putting values in equation 1, we get:

\text{Probability of getting a white or blue or orange ball}=\frac{52}{64}=0.81

  • <u>For c:</u>

Number of favorable outcomes (ball must be white or orange) = [18 + 15] = 33

Total number of outcomes = 64

Putting values in equation 1, we get:

\text{Probability of getting a white or orange ball}=\frac{33}{64}=0.52

Probability of getting a ball which is neither white or orange = [1 - (Probability of getting a white or orange ball)] = [1 - 0.52] = 0.48

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3 years ago
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Norma-Jean [14]
1. find our slope: y2 - y1/ x2- x 1

-9 + 4= -5
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m = 0

2. now we need to use our point-slope form to find our y intercept

point-slope form: y - y1 = m(x - x1)

y + 4 = 0(x - 2)

distribute:
y + 4 = 0x

3. get y by itself

y + 4 - 4 = y
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4. write in slope-intercept form:

y = 0x - 4
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wariber [46]

Answer:

y+3 = 1/2 (x-4)

Step-by-step explanation:

We can write the equation in point slope form

y-y1 = m(x-x1)

The slope is m and the point is (x1,y1)

y - -3 = 1/2(x -4)

y+3 = 1/2 (x-4)

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