X = (2^2)^(2.5) 
<span>x = 2^(2 * 2.5) </span>
<span>x = 2^5 </span>
<span>x = 32 
</span>y^(-3/2) = 125 
<span>y^(-3) = 125^2 </span>
<span>y^(-3) = (5^3)^2 </span>
<span>y^(-3) = (5^2)^3 </span>
<span>y^(-3) = 25^3 </span>
<span>y = 25^(-1) </span>
<span>y = 1/25 </span>
<span>x/y => </span>
<span>32 / (1/25) => </span>
<span>32 * 25 => </span>
<span>800 is the simplest form of above
</span>
        
             
        
        
        
Answer:
z-test
hu=50
Step-by-step explanation:
 
        
             
        
        
        
I would say C. 5.516 m.
Hope this helps !
Photon
        
                    
             
        
        
        
Supposing that the integers are x, y and z, and that their average is 8, then
x+y+z
-------- = 8, or x + y + z = 24.
    3
Let's experiment.    Making up a table, we get:
x   y   z   sum (sum MUST be 24)
5  9  10    24
4  9   11    24
3  10  11   24
2   11 11    24
1   11  12   24
1   10  13   24
1    1   22   24
Can't choose integers smaller than 1, so it appears that 22 is the largest possible integer that could be one of x, y and z.
        
             
        
        
        
There are 26 letters with 5 vowels. That is a 5/26 chance of randomly picking a vowel. Hope this is helpful!