X = (2^2)^(2.5)
<span>x = 2^(2 * 2.5) </span>
<span>x = 2^5 </span>
<span>x = 32
</span>y^(-3/2) = 125
<span>y^(-3) = 125^2 </span>
<span>y^(-3) = (5^3)^2 </span>
<span>y^(-3) = (5^2)^3 </span>
<span>y^(-3) = 25^3 </span>
<span>y = 25^(-1) </span>
<span>y = 1/25 </span>
<span>x/y => </span>
<span>32 / (1/25) => </span>
<span>32 * 25 => </span>
<span>800 is the simplest form of above
</span>
Answer:
z-test
hu=50
Step-by-step explanation:
I would say C. 5.516 m.
Hope this helps !
Photon
Supposing that the integers are x, y and z, and that their average is 8, then
x+y+z
-------- = 8, or x + y + z = 24.
3
Let's experiment. Making up a table, we get:
x y z sum (sum MUST be 24)
5 9 10 24
4 9 11 24
3 10 11 24
2 11 11 24
1 11 12 24
1 10 13 24
1 1 22 24
Can't choose integers smaller than 1, so it appears that 22 is the largest possible integer that could be one of x, y and z.
There are 26 letters with 5 vowels. That is a 5/26 chance of randomly picking a vowel. Hope this is helpful!
