Is 5.3 repeating rational

By definition represent "the cost advantages that enterprises obtain due to their scale of operation, with cost per unit of output decreasing with increasing scale" and thats the corrct option since if we increase the order we have a lower price.

Step-by-step explanation:

Assuming the following options we analyze one by one to select the correct one

A. A move to minimum efficient scale

By definition the minimum efficient scale (MES) or efficient scale of production is "the lowest point where the plant can produce such that its long run average costs are minimized" but thats not the case since the department order new planes and the costs are not minimized .

B. The law of diminishing returns

The law of diminishing marginal returns says that "at some point, adding an additional factor of production results in smaller increases in output" but that's not the case since we don't have smaller increases in output.

C. The loss of economies of scale

By definition represent "the cost advantages that enterprises obtain due to their scale of operation, with cost per unit of output decreasing with increasing scale" and thats the corrct option since if we increase the order we have a lower price.

D. An increase in fixed cost

That's False since on this case we don't have a fixed cost, the cost on this case depend on the size of the order.

4 0

3 years ago

Can someone help please asap

ch4aika [34]

Sn = (a1) x (1 - r^n) / (1 - r)

Substituting the known values:

S5 = (6) x (1 - (1/3)^5) / (1 - 1/3) = 242/27 = 8 24/27 = 8 8/9

3 0

3 years ago

PLEASE HELP AND SHOW WORK!!

Nastasia [14]

Answer:

Pipe 1 alone fills a tank in 10 min

Pipe 2 alone fills the tank in 20 min

If both are turned on together, how long will it take to fill the tank???

Pipe 1 fills at the RATE of 1/10th tank per min

Pipe 2 fills at the RATE of 1/20th tank per min

Pipe 1 + Pipe 2 fills at the rate of 1/10+1/20 or 3/20th tank per min

Let x= time to fill the tank

(3/20)(x)=1 Where 1 denotes a full tank (Multiply both sides by 20)

3x=20

x=6 2/3 min----------both working together

NOW YOUR PROBLEM

Let x= amount of time for smaller pipe to fill the tank

Then (x-5)=amount of time for larger pipe to fill the tank

NOW HERE'S WHERE THE RECIPROCAL COMES IN:

The smaller pipe fills the tank at the RATE of 1/x cu units per min

The larger tank fills the tank at the RATE of 1/(x-5) cu units per min

Together, they fill the tank at the rate of 1/x+(1/(x-5)) cu units per min

But now we are told that together the fill the tank in 11 1/9 minutes. so our equation to solve is:

(1/x+(1/(x-5))(11 1/9)=1 where 1 denotes a full tank. In fact, in each of the above reciprocals, the 1 denotes a full tank.

So, dividing both sides by 11 1/9, we get:

1/x+(1/(x-5)=1/(11 1/9)-------------- which is your equation

I assume that you have no problems solviing this eq.

Hope this helps----ptaylor

Step-by-step explanation:

7 0

3 years ago