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3 years ago

Please Help... Thanks!

Mathematics

1 answer:

Brut [27]3 years ago

6 0

Answer:

The system of linear inequalities to represent the graph is:

(1) y<=6 and

(2) y>=x

Step-by-step explanation:

The graph is:

1) The region below the horizontal line y=6: y<=6

2) The region above the oblique line that passes through the points:

Origin: O=(0,0)→P1=(0,0)=(x1,y1)→x1=0, y1=0

P2=(5,5)=(x2,y2)→x2=5, y2=5

Slope: m=(y2-y1)/(x2-x1)

m=(5-0)/(5-0)

m=(5)/(5)

m=1

Equation Point-slope:

y-y1=m(x-x1)

y-0=1(x-0)

y=1(x)

y=x

Above the line y=x: y>=x

Then the system of linear inequalities to represent the graph is:

(1) y<=6 and

(2) y>=x

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Sanjay graphs a quadratic function that has x-intercepts of –3 and 7. Which functions could he have graphed?

kykrilka [37]

we will select each options and find zeros

(a)

$g(x)=x^2-4x-21$

for finding x-intercept , we can set g(x)=0

and then we can solve for x

$g(x)=x^2-4x-21=0$

now, we can factor it

$(x-7)(x+3)=0$

we get

$x=7,x=-3$

so, this is TRUE

(b)

$g(x)=(x-3)(x+7)$

we can set it to 0

and then we can solve for x

$g(x)=(x-3)(x+7)=0$

we get

$x=3,x=-7$

so, this is FALSE

(c)

$g(x)=3x^2-12x-63$

we can set it to 0

and then we can solve for x

$g(x)=3x^2-12x-63 =0$

$3(x^2-4x-21) =0$

$3(x-7)(x+3) =0$

$x=-3,x=7$

so, this is TRUE

(d)

$g(x)=-(x+3)(x-7)$

now, we can set it to 0

and then we can solve for x

$g(x)=-(x+3)(x-7)=0$

$x=-3,x=7$

so, this is TRUE

(e)

we have

$g(x)=x^2+4x-21$

now, we can set it to 0

and then we can solve for x

$g(x)=x^2+4x-21=0$

$(x+7)(x-3)=0$

$x=-7,x=3$

so, this is FALSE

5 0

2 years ago

Read 2 more answers

Calculate 58^2-42^2 ??

sladkih [1.3K]

Answer:

1600

Step-by-step explanation:

As you can see, this is a difference of squares. We can plug it into our differences of squares formula to get the answer:

(a+b)(a-b)

(58+42)(58-42)

(100)(16)

= 1600

Hope you learned something!

6 0

2 years ago

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cupoosta [38]

Answer:

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Step-by-step explanation:

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3 years ago

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Elanso [62]

Answer:

Step-by-step explanation:256

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3 years ago

The distances between three cities on a map are 45 miles, 56 miles, and 72 miles. Do the positions of

ollegr [7]

Answer:

The position of the three cities do not form a right-triangle.

Step-by-step explanation:

There are three cities on a map (say A, B, and C).

Now, the distances between them are 45 miles, 56 miles, and 72 miles.

i.e. AB= 45 miles, BC= 56 miles and CA =72 miles.

If the three cities A, B, C form a right-angled triangle on the map, then applying Pythagoras Theorem AB² +BC² =AC²

or, AC= √(AB² +BC²) must be satisfied.

Now, right-hand side of the above equation =√(45²+56²) =71.84 ≠ 72 (AC)

Hence, Right-hand side ≠ Left-hand side.

Therefore, the positions of the three cities do not form a right triangle. (Answer)

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3 years ago