Let n = 0, 1, 2, 3, 4, 5, 6, 7....
When n = 0 then 0^2 + 0 = 0. n = 1 we have 1^2 + 1 = 2. And when n = 2 we have 2^2 + 2 = 6. When n= 3 we have 3^2 + 3 = 12. When n = 4 we have 4^2 + 4 = 20. When n = 5 we have 5^2 + 5 = 30. When n = 6 = 6^2 + 6 = 42. And finally when n = 7 we have 7^2 + 7 = 56. So at n = 1, 2, ...7, ... Our values are = 2, 6, 12, 20, 30, 42, and 56. It is obvious that n is always an even number. Hence n^2 + n is always an even integer for all positive integers.
When n = -1 we have (-1)^2 - 1 = 0 when n = -2 we have (-2)^2 -2 = 2. When n = -3 we have (-3)^2 - 3 = 6. When n = -4 we have (-4)^2 - 4 = 16 - 4 =12. When n =-5 we have (-5)^2 -5 = 20. When n = -6 we have (-6)^2 - 6 = 30. When n = (-7)^2 - 7 = 42. Hence n^2 + n is always even for all integers
Opposites:
a. -3
b. 9
c. 5
d. -12
Answer:
Step-by-step explanation:
How many books are there?
6+5+4+3 = 18 books total
How many are adventure books?
3
3 out of 18 books are adventure books
Robero has a 3/18 probability of choosing an adventure book.
Your teacher might want that probability in the lowest possible form. That is because it is the easiest to use and to understand.
You can do this by dividing both numbers by the "numerator" which is the first number in the fraction, (the adventure book count).
3/3 = 1
18/3 = 6
So the fraction can be reduced to 1/6.
Robero has a 1/6 chance of choosing an adventure book.
Answer:
literacy rate
Step-by-step explanation:
reasearchers know hot to read and write
