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Lelu [443]
3 years ago
6

Which expression is equivalent to the given expression? (3m-4)^3(3m^5)

Mathematics
1 answer:
BabaBlast [244]3 years ago
8 0

Answer: D.

Step-by-step explanation:

You want to cube each term in the parentheses. When you take an exponent to an exponent, you just multiply them. You get (27m^-12). In order to get rid of that negative exponent, you should put a one over the m term and make -12, +12:

(\frac{27}{m^12} )(3m^5)

Multiply the numerators to get:

81m^5

You now have:

\frac{81m^5}{m^12}

When you divide exponents, you subtract them. 5 - 12 = -7

You have m^-7 which is the same as 1/m^7. Finally, mulitply that by the 81 we left out to get the answer of D.

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Gemiola [76]

Answer:

volume=πr²h

75.36=<u>2</u><u>2</u><u>×</u>3×3×h

7

75.36=<u>198×</u>h

7

7×75.36=<u>198×h×7</u>

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6 0
3 years ago
Tan(x-y) if cscx=13/5 and coty=4/3
ehidna [41]

Answer:

tan(x-y) = -16/63

Step-by-step explanation

Tan(x-y) if cscx=13/5 and coty=4/3

Given

coty = 4

1/tany = 4/3

Cross multiply

tan y = 3/4

Also since cscx = 13/5

1/sinx = 13/5

sinx = 5/13

Since sinx = opp/hyp

opp = 5

hyp = 13

Get the adjacent

hyp² = opp²+adj²

13² = 5²+adj²

adj² = 13² - 5²

adj² = 169 - 25

adj² = 144

adj = 12

cosx = adj/hyp

cosx = 12/13

tanx = sinx/cosx

tanx = (5/13)/(12/13)

tanx = 5/13 * 13/12

tan x = 5/12

tan(x-y) = tanx - tany/1+tanxtany

tan(x-y) = (5/12 - 3/4)/1+(5/12)(3/4)

tan(x-y) = (5-9/12)/1+5/16

tan(x-y) = -4/12/(21/16)

tan(x-y) = -1/3 * 16/21

tan(x-y) = -16/63

3 0
2 years ago
A vector is in standard position, with its terminal point in the second quadrant and an x-coordinate of –5. The vector has a mag
joja [24]

a.

The y-coordinate of the vector with its terminal point in the second quadrant is 6.

The magnitude of the vector, r = √(x² + y²) where x = x-coorcinate of vector = -5 and y = y-coordinate of vector.

Since r = √61 and r = √(x² + y²)

Making y subject of the formula, we have

y = √(r² - x²)  

Substituting the values of the variables into the equation, we have

y = √((√61)² - (-5)²)  

y = √(61 - 25)  

y = ±√36

y = ±6

Since r is in the second quadrant, its y-coordinate is positive.

So, y = 6

So, the y-coordinate of the vector with its terminal point in the second quadrant is 6.

b.

The direction angle of the vector with its terminal point in the second quadrant is 130°

The direction angle of the vector is gotten from tanФ = y/x

Subsstituting x and y into the equation, we have

tanФ = y/x

tanФ = 6/-5

tanФ = -1.2

tan(180° - Ф) = 1.2

Taking inverse tan of both sides, we have

180° - Ф = tan⁻¹(1.2)

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Ф = 180° - 50.2°

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Ф ≅ 130° to the neares whole number

The direction angle of the vector with its terminal point in the second quadrant is 130°.

Learn more about vectors here:

brainly.com/question/18478651

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katrin [286]

Answer:

9 am

Step-by-step explanation:

8 0
2 years ago
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The proportion of businesses who did not respond = 54.67%

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The proportion of businesses who did not respond =

82/150 x 100

54.67%

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3 years ago
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