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Ket [755]
3 years ago
12

If the angles 51 degrees, 88 degrees, and 41 degrees formed a tirangle what type of angle would it be

Mathematics
1 answer:
timurjin [86]3 years ago
7 0
The triangle is a scalene acute triangle.
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What does this mean
kow [346]
I would pick B because A will take too long C I don`t know what Y is.
8 0
3 years ago
Use stoke's theorem to evaluate∬m(∇×f)⋅ds where m is the hemisphere x^2+y^2+z^2=9, x≥0, with the normal in the direction of the
ludmilkaskok [199]
By Stokes' theorem,

\displaystyle\int_{\partial\mathcal M}\mathbf f\cdot\mathrm d\mathbf r=\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S

where \mathcal C is the circular boundary of the hemisphere \mathcal M in the y-z plane. We can parameterize the boundary via the "standard" choice of polar coordinates, setting

\mathbf r(t)=\langle 0,3\cos t,3\sin t\rangle

where 0\le t\le2\pi. Then the line integral is

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=2\pi}\mathbf f(x(t),y(t),z(t))\cdot\dfrac{\mathrm d}{\mathrm dt}\langle x(t),y(t),z(t)\rangle\,\mathrm dt
=\displaystyle\int_0^{2\pi}\langle0,0,3\cos t\rangle\cdot\langle0,-3\sin t,3\cos t\rangle\,\mathrm dt=9\int_0^{2\pi}\cos^2t\,\mathrm dt=9\pi

We can check this result by evaluating the equivalent surface integral. We have

\nabla\times\mathbf f=\langle1,0,0\rangle

and we can parameterize \mathcal M by

\mathbf s(u,v)=\langle3\cos v,3\cos u\sin v,3\sin u\sin v\rangle

so that

\mathrm d\mathbf S=(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv=\langle9\cos v\sin v,9\cos u\sin^2v,9\sin u\sin^2v\rangle\,\mathrm du\,\mathrm dv

where 0\le v\le\dfrac\pi2 and 0\le u\le2\pi. Then,

\displaystyle\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S=\int_{v=0}^{v=\pi/2}\int_{u=0}^{u=2\pi}9\cos v\sin v\,\mathrm du\,\mathrm dv=9\pi

as expected.
7 0
3 years ago
Please due in an hour !!!
Masja [62]
The correct answer is c.
6 0
2 years ago
Read 2 more answers
Find the indicated length or angle measure (to the nearest tenth).
skad [1K]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Explain the formula to use

Using the cosine rule which states that:

z^2=x^2+y^2-2xy\cos Z

STEP 2: Write the given sides

x=4,y=6,Z=41^{\circ},z=?

STEP 3: Find the value of z

\begin{gathered} By\text{ substitution,} \\ z^2=4^2+6^2-2(4)(6)\cos41 \\ z^2=16+36-48cos41 \\ z^2=52-36.22605985 \\ z^2=15.77394015 \\ z=\sqrt{15.77394015} \\ z=3.971641997 \\ z\approx4.0 \end{gathered}

Hence, the indicated length is 4.0

4 0
1 year ago
Can you please help me l will give brainliest​
yKpoI14uk [10]

Answer:

question 1 and 3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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