What is the greatest common factor for 9, 36, & 189
2 answers:
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In this we know all three zeros and one point from which the graph pass.
So we will let specific cubic polynomial function of the form
As we know zeros are that point where we will get value of function equal to zero. So it is basically in form
SO in given question zeros are (2 , 0) , (3, 0) and (5,0)
So we can say
So required equation is
![= a[(x^2 - 2x - 3x + 6)(x-5)]](https://tex.z-dn.net/?f=%3D%20a%5B%28x%5E2%20-%202x%20-%203x%20%2B%206%29%28x-5%29%5D)
![= a[(x^2 - 5x+6)(x-5)]](https://tex.z-dn.net/?f=%3D%20a%5B%28x%5E2%20-%205x%2B6%29%28x-5%29%5D)
Now we have one point (0 , -5) from which graph passes.
So we say at x = 0 , f(x) = -5
So required equation of cubic polynomial is
For finding y - intercept we simply plugin x = 0 in given equation.
As we know at x = 0 , value of function is -5.
So y - intercept is -5.
So we will let specific cubic polynomial function of the form
As we know zeros are that point where we will get value of function equal to zero. So it is basically in form
SO in given question zeros are (2 , 0) , (3, 0) and (5,0)
So we can say
So required equation is
Now we have one point (0 , -5) from which graph passes.
So we say at x = 0 , f(x) = -5
So required equation of cubic polynomial is
For finding y - intercept we simply plugin x = 0 in given equation.
As we know at x = 0 , value of function is -5.
So y - intercept is -5.
Answer:
See explanation
Step-by-step explanation:
A. Gasoline fill-up fee = $4.50
Cost per hour = $40
Average cost = C
Number of hours the scootcar is rented = h
Cost per h hours = $40h
Total cost = $40h + $4.50
Hence,
C = 40h+4.5
B. To plot the graph of the function, find h- and C- intercepts.
When h = 0, then C = 4.5, and we have point (0,4.5)
When C = 0, then 0 = 40h + 4.5, h = -45/400 = -0.1125, and we have point (-0.1125,0)
Plot these two points and connect them with a straight line.
Graph is attached, but you should take only that part of the graph that corresponds to points with h > 0, because the number of hours cannot be negative
