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Lynna [10]
3 years ago
13

What is the value of n when (9)^2n-1 =(27)^n+2

Mathematics
2 answers:
Sedaia [141]3 years ago
5 0

Answer:

n = 8

Step-by-step explanation:

Using the rule of exponents

(a^m)^{n} = a^{mn}

Given

(9)^{2n-1} = (27)^{n+2}, then

(3^2)^{2n-1} = (3^3)^{n+2}

3^{4n-2} = 3^{3n+6}

Since the bases on both sides are equal, both 3 then equate the exponents

4n - 2 = 3n + 6 ( subtract 3n from both sides )

n - 2 = 6 ( add 2 to both sides )

n = 8

LenKa [72]3 years ago
3 0

Answer:

n = 8

Step-by-step explanation:

9²ⁿ⁻¹ = 27ⁿ⁺²

(3²)²ⁿ⁻¹ = (3³)ⁿ⁺²

3⁴ⁿ⁻² = 3³ⁿ⁺⁶

4n - 2 = 3n + 6

4n - 3n = 6 + 2

n = 8

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