Answer:
256/3 = 85 1/3 square inches
Step-by-step explanation:
The dimensions of the first inscribed triangle are 1/2 those of the original, so its area is (1/2)² = 1/4 of the original. The area of the original is ...
A = (1/2)bh = (1/2)(16/√2)(16/√2) = 64 . . . . square inches
The sum of an infinite series with first term 64 and common ratio 1/4 is ...
S = a1/(1 -r) . . . . . . for first term a1 and common ratio r
= 64/(1 -1/4) = 64(4/3) = 256/3 . . . . square inches
The sum of the areas of the triangles is 256/3 = 85 1/3 square inches.
we are given
6 × 8 = 48
we know that
commutative property of multiplication:

now, we will verify each options
option-A:
we have
6 × 8 = 48
now, we can find it's commutative
so, we get
8 × 6 = 48
so, this is TRUE
option-B:
we have
6 × 8 = 48
now, we can find it's commutative
so, we get
8 × 6 = 48
so, this is FALSE
option-C:
we have
6 × 8 = 48
now, we can find it's commutative
so, we get
8 × 6 = 48
so, this is FALSE
Answer:
im so sorry but i need to finish my challenge
Step-by-step explanation:
B- Not sure if it's a line
C- y=(-x/2)-6
D- y=4x-12
E- y=(2/5)x-10