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zvonat [6]
3 years ago
15

I can List all the factors of each number. The I can circle the factors that are common to all three numbers. Factors of: 30, 24

, 36
Mathematics
1 answer:
scoundrel [369]3 years ago
7 0

Answer:

1,2,3,6

Step-by-step explanation:

30>1,2,3,5,6,10,15,30

24>1,2,3,4,6,8,12,24

36>1,2,3,4,6,9,12,18,36

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What percent of 60 is 15?
kvasek [131]
Well the first one you have to divide both sides by 60 to get x. 
=60x/60=1500/60 
x=25
your answer is 25%

second one...think of it as 18/50. multiply by 2 and you get 36/100 
your answer is 36%
4 0
3 years ago
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Please help :))) Find the area.
diamong [38]

Answer:

a. 140 in²

Step-by-step explanation:

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4 0
3 years ago
Evaluate the iterated integral 2 0 2 x sin(y2) dy dx. SOLUTION If we try to evaluate the integral as it stands, we are faced wit
nignag [31]

Answer:

Step-by-step explanation:

Given that:

\int^2_0 \int^2_x \ sin (y^2) \ dy dx \\ \\ \text{Using backward equation; we have:} \\ \\  \int^2_0\int^2_0 sin(y^2) \ dy \ dx = \int \int_o \ sin(y^2) \ dA \\ \\  where; \\ \\  D= \Big\{ (x,y) | }0 \le x \le 2, x \le y \le 2 \Big\}

\text{Sketching this region; the alternative description of D is:} \\ D= \Big\{ (x,y) | }0 \le y \le 2, 0 \le x \le y \Big\}

\text{Now, above equation gives room for double integral  in  reverse order;}

\int^2_0 \int^2_0 \ sin (y^2) dy dx = \int \int _o \ sin (y^2) \ dA  \\ \\ = \int^2_o \int^y_o \ sin (y^2) \ dx \ dy \\ \\ = \int^2_o \Big [x sin (y^2) \Big] ^{x=y}_{x=o} \ dy  \\ \\=  \int^2_0 ( y -0) \ sin (y^2) \ dy  \\ \\ = \int^2_0 y \ sin (y^2) \ dy  \\ \\  y^2 = U \\ \\  2y \ dy = du  \\ \\ = \dfrac{1}{2} \int ^2 _ 0 \ sin (U) \ du  \\ \\ = - \dfrac{1}{2} \Big [cos  \ U \Big]^2_o \\ \\ =  - \dfrac{1}{2} \Big [cos  \ (y^2)  \Big]^2_o  \\ \\ =  - \dfrac{1}{2} cos  (4) + \dfrac{1}{2} cos (0) \\ \\

=  - \dfrac{1}{2} cos  (4) + \dfrac{1}{2} (1) \\ \\  = \dfrac{1}{2}\Big [1- cos (4) \Big] \\ \\  = \mathbf{0.82682}

5 0
3 years ago
How do you write the following linear equations in standard form ?
ANTONII [103]
Hi<span>, Victoriasoto93p63zva!

To rewrite these equations in standard form you need to understand that standard form looks something like this Ax+By=C, now obviously there will be variations like </span>Ax-By=C or -Ax+By=C, etc..., but for these expressions, they would look like this:
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-</span><span>ASIAX</span><span> </span><span>Frequent Answerer</span>
4 0
3 years ago
15 and 16 pls thank you ASAP ASAP
Delicious77 [7]
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5 0
3 years ago
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