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Mnenie [13.5K]
3 years ago
6

Use the Pythagorean Theorem to determine the lengths of QT and RS Show your work

Mathematics
1 answer:
Alexus [3.1K]3 years ago
8 0

WHAT WAS THE ANSWER I HAVE THAT TEST RN

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Match each transformations to the shape it maps shape 1 onto ... Drag the tiles to correct boxes to complete the pairs
rosijanka [135]

Answer:

shape V -----> 90° counterclockwise

shape II ------> 90° clockwise

shape III -----> translation

shape IV -----> 180° rotation


7 0
3 years ago
Read 2 more answers
What is the product of (X4/3)(X2/3) ?
katrin [286]
Hi, the answer to this would be x6/9. I'm assuming the x4/3 and x2/3 are fractions and the x's aren't exponents. Now how I got x6/9 is shown here.

1st Step: Started off by regrouping the terms
1/3x3 x^4x^2

2nd Step: we can easily simplify 3x3 to just 9. And now we're left with 1/9x^4x^2

3rd Step: Now we can simplify the 1/9 to just x^4x^2/9

4th Step: Now we can use the product rule which is simple. So We add the exponents and simplify it to just one exponent. So x4+2=6 that simplifies to just x^6.

Final Answer: x^6/9.
Hope this helped you :)
7 0
4 years ago
The power goes out as Sandra is trying to get dressed. If she has 9 white T-shirts and 11 colored T-shirts in her drawer, is it
Lapatulllka [165]
Because she has more COLORED shirts then WHITE shirts it is likely she will pick a COLORED shirt.

11 +9 = 20 total shirts

 probability for a colored one = 11/20

8 0
3 years ago
PLZ HELP I WILL GIVE BRAINLIEST...
Delicious77 [7]

Answer:

a. 6

b. 7

c. (b) Kira's

why? b. it has the large sample size

Step-by-step explanation:

7 0
3 years ago
Which point is in the solution set of the given system of inequalities 3x+y>-3,x+2y<4
Dima020 [189]
Step 1. Solve both inequalities for y:
3x+y\ \textgreater \ -3
y\ \textgreater \ -3x-3

x+2y\ \textless \ 4
2y\ \textless \ -x+4
y\ \textless \ - \frac{1}{2} x+2

Step 2. To check a point in the solution of the given system of inequalities, look for the intercepts of the lines -3x-3 and - \frac{1}{2} x+2:

y=-3x-3 (1)
y=- \frac{1}{2} x+2 (2)

Replace (1) in (2):
-3x-3=- \frac{1}{2} x+2
Solve for x:
\frac{5}{2} x=-5
x=-2 (3)

Replace (3) in (1):
y=-3x-3
y=-3(-2)-3
y=6-3
y=3

We can conclude that the point (-2,3) is in the solution of the system if <span>inequalities</span>; also any point inside the dark shaded area of the graph of the system of inequalities is also a solution of the system.

4 0
3 years ago
Read 2 more answers
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