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3 years ago

The volume of a triangular prism with 5cm 7cm and 13 cm

Mathematics

1 answer:

inysia [295]3 years ago

5 0

7 × 5 × 13 = 455 455 ÷ 2 = 227.5

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Plzz help i really need an answer will give brainlyist

Verdich [7]

Answer:

the answer to what??

Step-by-step explanation:

7 0

3 years ago

Identify sinJ as a fraction and as a decimal rounded to the nearest hundredth.

KiRa [710]

In the given right triangle, the trigonometric ratio, sin J has a fractional value of 5/13 and a decimal value of 0.39.

In trigonometry, for a right triangle, the sine (sin) of any angle θ is given as the ratio of its opposite side to the hypotenuse of the triangle, that is, sin θ = (opposite side)/(hypotenuse).

In the question, we are asked to find the trigonometric ratio, sin J, for the given right triangle JKL.

The side opposite to angle J is KL, which has a value of 3 units.

The hypotenuse of the given right triangle is JK, which has a value of 7.8 units.

Thus, sin J can be calculated as:

sin J = KL/JK = 3/7.8 = 5/13 = 0.39.

Thus, in the given right triangle, the trigonometric ratio, sin J has a fractional value of 5/13 and a decimal value of 0.39.

Learn more about trigonometric ratios at

brainly.com/question/20367642

#SPJ1

8 0

2 years ago

Which expression is equivalent to 3 square root 64k^12

Veronika [31]

$\sqrt[3]{64k^{12}} = \sqrt[3]{4^{3}}\times \sqrt[3]{k^{12}} = 4k^{4}$

3 0

3 years ago

Read 2 more answers

I just need #2 thanks for giving your time to help me

SVEN [57.7K]

2.
1099.99x 0.58 =637.9942
1099.99-637.9942= 461.9958
461.9958x 0.065=30.029727
461.9958-30.029727=431.967073

The answer round is 431.96

3.
42.95x1/5= 8.59
42.95-8.59 = 34.56
34.56 x 0.07=2.4192
34.56-2.4192= 32.1408
Round it is 32.14

4.
1250x0.85= 1062.5
1250-1062.5 =187.5

7 0

3 years ago

Write a polynomial in standard form with the zeros -4,0, 1, and 4.

gavmur [86]

Answer: $x^4-x^3-16x^2+16x$

Step-by-step explanation:

Factor theorem : If x=a is a zero of a polynomial p(x) then (x-a) is a factor of p(x).

Given: Zeroes of polynomial : -4,0, 1, and 4.

Then Factors = $(x-(-4)), (x-0), (x-1) and (x-4)$ [By factor theorem ]

$=(x+4), (x-0), (x-1) and (x-4)$

Multiplying these factors to get polynomial in standard form.

$(x+4)\times(x-0)\times(x-1)\times(x-4) \\\\= x(x+4)(x-4)(x-1)\\\\= x(x^2-4^2)(x-1)\\\\= x(x^2-16)(x-1)\\\\= x(x^2-16)(x-1)\\\\=x(x^2x+x^2\left(-1\right)+\left(-16\right)x+\left(-16\right)\left(-1\right))\\\\= x(x^3-x^2-16x+16)\\\\=x^4-x^3-16x^2+16x$

Hence, B is the correct option.

8 0

3 years ago