7 - 8 + x = 11 + 5how to resolve this equation.
1 answer:
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Answer:
c = 5
Step-by-step explanation:
The Pythagorean theorem states that in every right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the respective lengths of the legs. It is the best-known proposition among those that have their own name in mathematics.
Pythagoras theorem
In every right triangle the square of the hypotenuse is equal to the sum of the squares of the legs.
If in a right triangle there are legs of length a and b the measure of the hypotenuse is c then the following relation is fulfilled:
With a = 3 and b = 4
Answer:
1a - no
1b - yes
1c - no
2 - 1.5 grams of protein
3 - a solution to this equation tells us how many grams of protein/fat there could be depending on how many grams of the other there are. a solution to this is 6 grams of protein and 4 grams of fat.
Step-by-step explanation:
1a
4(5)+9(2)=60
20+18=60
38=60
the equation is false
1b
4(10.5)+9(2)=60
42+18=60
60=60
the equation is true
1c
4(8)+9(4)=60
32+36=60
68=60
the equation is not true
2
plug in 6 for the f value
4p+9(6)=60
4p+54=60
subtract 54 from both sides
4p=6
divide both sides by 4 to get p alone
p=1.5
3
a possible solution can be seen by graphing the equation using the intercepts. the intercepts for this equation are (15,0) and (0,6.6). attached is an image of the graph. the points where the line crosses are possible solutions. the line crosses the point (6,4) on the graph, which represents 6 grams of protein and 4 grams of fat. you can also check this by plugging these values into the equation.
First, find what percentage of students had 3 or more by adding up your known percents:
45% + 23 % + 21% + x% = 100%
x = 11%
Since you're given that 96 students had 2 or more, you add up the percentages of 2 and 3 or more:
11 + 21 = 32%
Now set up a proportion that relates it to the whole:
This will allow you to find the total number of students at the school.
Cross multiplying and solving for x results in 300 total students.
Question 1:
45% had one or more absences. 45% of 300 students is 135 students.
Question 2:
As we found before, 11% of students had three or more. 11% of 300 is 33 students.
45% + 23 % + 21% + x% = 100%
x = 11%
Since you're given that 96 students had 2 or more, you add up the percentages of 2 and 3 or more:
11 + 21 = 32%
Now set up a proportion that relates it to the whole:
This will allow you to find the total number of students at the school.
Cross multiplying and solving for x results in 300 total students.
Question 1:
45% had one or more absences. 45% of 300 students is 135 students.
Question 2:
As we found before, 11% of students had three or more. 11% of 300 is 33 students.