3 years ago

Write a phrase for y + 9

Mathematics

2 answers:

faltersainse [42]3 years ago

6 0

The sum of y and 9

Hope this helps

serg [7]3 years ago

5 0

y and 9 added. its very easy. you can do "the sum of" or "_ and _ added"

You might be interested in

Can some help me with this 5th grade matg

harkovskaia [24]

Plus all month to gether
three months have 1/2 inches
one month has 3/4 inches
one month has 1+1/4 inches
one month has 1+1/2 inches
one month has 2 inches
two months have 2+1/4 inches
one month has 2+1/2 inches
two months have 3 inches
totally sum of them = 20 inches

4 0

3 years ago

Read 2 more answers

Why the neutron has no charge?

BigorU [14]

BECAUSE OF THE CHARGE THAT MAKES IT

7 0

3 years ago

Read 2 more answers

Hi, so I know the answer to this problem (now that I got it wrong) but I'm not quite sure why I was wrong, help?

melisa1 [442]

2x² + 2x + ? = x

⇒ ? = x - 2x² - 2x

⇒ ? = -2x² - x

Your answer is incorrect because 2x² - x² would mean x² is part of the answer, which is clearly incorrect.

4 0

2 years ago

Read 2 more answers

Someone help please, please be correct.

saveliy_v [14]

Answer:

Which question?

Step-by-step explanation:

5 0

3 years ago

Solve y' + 2xy = 2x^3, y(0) = 1

nlexa [21]

Multiply both sides by $e^{x^2}$ , then you get

$e^{x^2}+2xe^{x^2}y=2x^3e^{x^2}$
$\left(e^{x^2}y\right)'=2x^3e^{x^2}$
$e^{x^2}y=\displaystyle2\int x^3e^{x^2}\,\mathrm dx$
$e^{x^2}y=e^{x^2}(x^2-1)+C$
$y=x^2-1+Ce^{-x^2}$

Given that $y(0)=1$ , you have

$1=-1+Ce^0\implies C=2$

so that the particular solution is

$y=x^2-1+2e^{-x^2}$

6 0

4 years ago